如何动态地将函数数组添加到 javascript 函数？

Question

I do have this structure:

db.collection('users')

and want to make this:

db.collection('users')
   .where('works', 'array-contains', 'CASE_A')
   .where('works', 'array-contains', 'CASE_B')
   .where('works', 'array-contains', 'CASE_C')
   ...

In this case, I will make an array of
(( .where('works', 'array-contains', ${variable} ))

and i will add this in the beginning db.collection('users'), how can i make this?

Answer 1

Just make an inline array:

db.collection('users')
   .where('works', 'array-contains', ['CASE_A', 'CASE_B', 'CASE_C'])

Or use a variable if you want:

const array = ['CASE_A', 'CASE_B', 'CASE_C']
db.collection('users')
   .where('works', 'array-contains', array)

If you actually want to find documents where all cases are present (not where any of the cases are present), you won't be able to use an array-contains type query. You will have to convert your array into an object and query it as shown in this question: Firestore: Multiple 'array-contains'

Answer 2

Please try this code.

 const makeItem = value => `.where('works', 'array-contains',${value}` const arrFuncs = [ makeItem('CASE_A'), makeItem('CASE_B'), makeItem('CASE_C'), ] const initialCmd = `db.collection('users')` eval(initialCmd + arrFuncs.join(''))