Yii WHERE IN 有多个 where

Question

I have a table that looks like this:

id
listingId
type
distance

Where listingId is a foreign key to a table of listings, type is a handle for type of place, and distance is just an integer. And I want to be able to get all listingIds that fulfil a set of 1-5 queries. This is what I have so far:

$records = MyActiveRecord::find()
            ->select('listingId')
            ->where(['and', 'type="hospital"', "distance <= 130"])
            ->orWhere(['and', 'type="airport"', 'distance <= 600'])
            ->all();

Now this will return all hits as expected, but what I'm after are just the listingIds that show up twice (in this scenario, if there are three WHERE clauses I would want the ones that have 3 hits, and so on).

I'm guessing I would have to go for a WHERE IN , but I'm not sure how to do that with a subquery?

Any suggestions? Thanks.

EDIT (specifying a bit)

So what I'm after is any listingIds that have both hospital and airport within the given distances. The query given above gives me any listingId where it's either of them. And in that case wherever there are two identical listingId it would mean that I have a match on both, and that's the listingId I want.

Answer 1

I ended up getting the way to do it with SQL, so in the end I just used findBySql and wrote out my query:

$distances = [ // will come from query
    [
        'type' => 'hospital',
        'distance' => 130
    ],
    [
        'type' => 'airport',
        'distance' => 600
    ]
];

$query = 'select listingId from myTable
      where type = "' . $distances[0]['type'] . '"
      and distance <= ' . $distances[0]['distance'];

foreach(array_slice($distances, 1) as $dist) {
    $query = 'select listingId from myTable
        where type = "' . $dist['type'] . '"
        and distance <= ' . $dist['distance'] . '
        and listingId in (' . $query . ')';
}

Which ends up looking something like this

select listingId from myTable
where type = 'bar'
and distance <= 130
and listingId in (
  select listingId from myTable
  where type = 'airport'
  and distance <= 600
)

Answer 2

$subQuery = MyActiveRecord::find()->select('listingId')->where(['and',['type' => 'airport'],['<=', 'distance', 600]]);
$records = MyActiveRecord::find()
                        ->select('listingId')
                        ->where(['and', ['type' => 'hospital'], ['<=', 'distance', 130]])
                        ->orWhere(['in', 'listingId', $subQuery])
                        ->all();