[英]How to use php or js to echo a default text when a field is missing?
I'm using custom field data, but a couple of posts have a certain custom fields empty.我正在使用自定义字段数据,但有几篇文章的某些自定义字段为空。
So I'd like to echo something like "if custom field exists = <?php echo get_post_meta($post->ID, 'mycustomfield', true); ?>
else = ' hello
'所以我想回应类似“如果自定义字段存在 =
<?php echo get_post_meta($post->ID, 'mycustomfield', true); ?>
else = ' hello
'
I suppose it's possible to do it both ways in php and javascript but I have no idea how to type the code in both way, as I'm still a fresh newbie.我想可以在 php 和 javascript 中以两种方式进行,但我不知道如何以两种方式键入代码,因为我仍然是一个新手。 Can you please help me?
你能帮我么? Thanks in advance!
提前致谢!
You mean something like:你的意思是这样的:
echo get_post_meta($post->ID, 'mycustomfield', true) ?
get_post_meta($post->ID, 'mycustomfield', true) : 'helo';
or the same assigning to a $customField
var:或相同的分配给
$customField
var:
$customField = get_post_meta($post->ID, 'mycustomfield', true);
echo $customField ? customField : 'helo';
? ?
This is done, in this example, using the ternary operator which seems to fit in what you ask for.在本例中,这是使用似乎符合您要求的三元运算符完成的。
Because I understand that get_post_meta($post->ID, 'mycustomfield', true)
is what returns your custom field.因为我知道
get_post_meta($post->ID, 'mycustomfield', true)
是返回您的自定义字段的原因。
In PHP +7 and major, if your variable contains the data you want to output you could use the null coalescing operator .在 PHP +7 和主要版本中,如果您的变量包含要输出的数据,则可以使用空合并运算符。
echo $customField ?? 'hello';
This will output $customField
if it exists, or hello
if it doesn't.这将输出
$customField
如果它存在,或者hello
如果它不存在。
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