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COUNT(DISTINCT()) OVER (PARTITION BY) 在 Presto (Athena)?

[英]COUNT(DISTINCT()) OVER (PARTITION BY) in Presto (Athena)?

I have the following table in an Athena (Presto) DB, let's call it table1 (simplified for this question):我在 Athena (Presto) DB 中有下表,我们称之为 table1(针对这个问题进行了简化):

  | serverdate | colA | colB | colC | hash
  |-------------------------------------------
0 | 2019-12-01 |    1 | OK   | 10   | hash1
1 | 2019-12-02 |    2 | OK   | 10   | hash2
2 | 2019-12-02 |    3 | NOK  | 100  | hash3
3 | 2019-12-01 |    3 | OK   | 0    | hash4
4 | 2019-12-03 |    6 | OK   | 1    | hash5
5 | 2019-12-05 |    8 | NOK  | 0    | hash6
6 | 2019-12-06 |    8 | NOK  | 0    | hash6

The following query is used to count how many distinct "hash" are in the table:以下查询用于计算表中有多少不同的“哈希”:

SELECT 'users' AS Type, round(count(DISTINCT hash)) AS uu
FROM table1

This is later used as a subquery, but it is not important for this question.这稍后用作子查询,但对于此问题并不重要。 In this example, result should be:在这个例子中,结果应该是:

  |  type | uu
  |-------------
0 | users | 6

What I want : I want to do this same counting, but grouping the results by colA .我想要什么:我想做同样的计数,但按colA对结果进行分组 My result should be something like this:我的结果应该是这样的:

  | colA | counthash
  |------------------
0 |    1 | 1
1 |    2 | 1
2 |    3 | 2
3 |    6 | 1
4 |    8 | 1

I think in using COUNT(DISTINCT(hash)) OVER (PARTITION BY colA), but as far as I know, COUNT(DISTINCT()) is not allowed as a window function in Presto.我认为在使用 COUNT(DISTINCT(hash)) OVER (PARTITION BY colA) 时,但据我所知, COUNT(DISTINCT()) 在 Presto 中不允许作为窗口函数。

Any ideas in how to do this?关于如何做到这一点的任何想法? Thanks.谢谢。

You shouldn't need a window function for this.您不应该为此需要窗口函数。 I'm not too familiar with presto per se, but does the following work?:我对 presto 本身不太熟悉,但以下方法是否有效?:

SELECT colA, round(count(DISTINCT hash)) AS uu
FROM table1
GROUP BY colA;

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