删除文本文件中的ip地址并替换为python中的随机ip地址

Question

import fileinput
import re
for line in fileinput.input('./log'):
    ips = re.findall(r'[0-9]+(?:\.[0-9]+){3}', line.rstrip())
    for ip in ips:
        re.sub(ip,'0.0.0.0',line.rstrip())
    print(line)

I tried this to replace ip address ith 0.0.0.0 but it dint work

Answer 1

So I have tested the above with a mixture of some other suggestions and the below finally worked for me

import fileinput
import re
from random import randint

filename = '/path/to/some/dir/syslog_.log'

for line in fileinput.input(filename):
    ips = re.findall(r'src=[0-9]+(?:\.[0-9]+){3}', line.rstrip())
    print(ips)
    with fileinput.FileInput(filename, inplace=True,backup='.bak') as file:
        for line in file:
            try:
                rand_ip = 'src=' + '%d.%d.%d.%d' % (randint(0,255),randint(0,255),randint(0,255),randint(0,255))
                print(line.replace(ips[0], rand_ip), end='')
            except Exception as e:
                raise
            else:
                pass
            finally:
                pass

The original file is cleared completely but a .bak file is created with all the original data + the new generated IP's. also the try except is just a template that needs to be filled but this is working with large files - I have tested with 2G file.

Answer 2

f = open('filename.txt','w')
from random import randint
# Ugly part:
str = '%d.%d.%d.%d' % (randint(0,255),randint(0,255),randint(0,255),randint(0,255))
f.write(str)
f.close()

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