根据关键字过滤数组

Question

I have an array:

 let array = [ 'Hello 1» (Foo_Test-Editable)', 'Hello 2» (Foo_Test-Editable)', 'Hello 3» (Foo_Test)', 'Foo_Test_4' ]; let searchKeyword = 'Foo_Test'; const result = array.filter(f => f.indexOf(searchKeyword) != -1); console.log(result);

Rules to find:

• array item should contain only Foo_Test , not Foo_Test+... plus some variations

Desired result is:

let result = [
    'Hello 3»  (Foo_Test)'
];

How to filter using the above rule?

Answer 1

If you can change the keyword to a regex...

 let array = [ 'Hello 1» (Foo_Test-Editable)', 'Hello 2» (Foo_Test-Editable)', 'Hello 3» (Foo_Test)', 'Foo_Test_4' ]; let searchKeyword = /Foo_Test[^-|_]/; const result = array.filter(f => searchKeyword.test(f)); console.log(result);

Answer 2

Add the parentheses around "Foo_Test" to distinguish it.

let srch = "(Foo_Test)"

 let arr = [ "Hello 1» (Foo_Test-Editable)", "Hello 2» (Foo_Test-Editable)", "Hello 3» (Foo_Test)", "FooText" ] let srch = "(Foo_Test)" const result = arr.filter( f => f.indexOf(srch)!= -1) console.log(result)

Answer 3

Actually your code is working , output was 3 array because all of them contained search value Foo_Test

(3) ["Hello 1» (Foo_Test-Editable)", "Hello 2» (Foo_Test-Editable)", "Hello 3»  (Foo_Test)"]

so add parentheses around (Foo_Test) to distinguish it from other, which will output specific value

(Foo_Test)