NodeJS：如何将变量添加到 JSON.parse() 的返回值中？

Question

I am very new to node.js.

I have a JSON that I am reading from a website. Without posting too much of the JSON, here's roughly what I'm looking at:

{
   "Head": {
      "Front": "80",
      "Side": "85",
      "Back": "75"
   },
   "Neck": {
      "Front": "65",
      "Side": "70",
      "Back": "60"
   }
}

I have a function that is formatted the following way:

function whichBodyPart(part, file, time) {
      var fileParse = JSON.parse(file);
      var type;
      switch(time.toLowerCase()){
        case ('9AM'):
            type = 'Front';
        break;
        case ('12PM'):
            type = 'Side';
        break;
        case ('3PM'):
            type = 'Back';
        break;
    }
    return fileParse.part.type;
  }

part is a user-passed-in value that, in this case, would either be "Head" or "Neck"

file is the un-parsed JSON file. I parse it in the function.

I know that to pull a specific element's value out of the JSON file I have here, I could do something along the lines of

return fileParse . Head.Back

and that would give me back the value "75". However, what I'm trying to do is navigate the JSON with the values from the variables part and type .

For example, if part is "Neck" and type is "Side", I want to retrieve the value "70" from the JSON. However, if the user input part as "Head" and type is "Front", I want to receive "80".

How do I make the return able to handle varying inputs?

Answer 1

You may use bracket notation of JavaScript to handle your varying inputs. Try:

return fileParse[part][type]