如何只获取数组的前 n%？

Question

I have a sorted array like this:

array [0, 0, 0, 1, 3, 5, 5, 6, 6, 6, 6, 8, 8, 8, 9, 9];

I want to view only the first n% of the array. I need the principle or advice on what to use (loop, slice, ...) to achieve this.

Answer 1

You could take the length of the array and the percent value and slice the array.

 function getPercent(array, percent) { return array.slice(0, Math.ceil(array.length * percent / 100)); } var array = [0, 0, 0, 1, 3, 5, 5, 6, 6, 6, 6, 8, 8, 8, 9, 9]; console.log(...getPercent(array, 10)); console.log(...getPercent(array, 20)); console.log(...getPercent(array, 30));