在嵌套列表中搜索

Question

EDIT

No longer getting list error after making suggested changes but still not returning any matches. Code now:

# all ingredients, represented by numbers: 0= empty selection 1=rice 2=spice 3=vegetable 
allIng = [0,1,2,3]

#Each individual recipe(r)

# Veggie Rice Balls
r1 = (0,1,3)

# Curry Rice
r2 =(0,1,2)

# Herb Sauté
r3 = (0,2,3)

# Vegetable Curry
r4 = (1,2,3)


# all recipes on one list 

allRec = [r1,r2,r3,r4]


#ingredients picked
iP = []
#ingredient count
iC = 1

#User given option to pick up to 3 ingredients
while iC <= 3:
    pitem = int (input ("Pick up to 3 items "))

    if pitem in allIng:
        iP.append(pitem)
        print(iP)
        iC += 1
    else:
        print ("Incorrect entry, please pick again")

#sort list
iP.sort()
tuple(iP)

#compare iP to allRec looking for matches
if iP in allRec:

    matches = set (iP) & set(allRec)
    print ("Matches:",matches)

Trying to get it print out which recipe matched and if possible tag the name of the recipe itself.

Answer 1

Lists are unhashable since they can be modified during runtime. So instead of lists, try using (non-mutable) tuples - you can define r1 through r4 using parentheses instead of brackets, and convert iP to a tuple after sorting. You can then use sets of tuples with no issues.

Answer 2

This is because of allRes is a list of the list. Which cannot be converted to the Set.

To get the index of the recipe or recipe you can use the following snippet.

index = allRec.index(iP)
recipe = allRec[index]

You will need no change all the recipes to the set; if ingredients are entered in a different order.