将元组转换为列表时，Python 列表索引超出范围

Question

As studying Python I got stuck in a Problem where GeeksforGeeks is telling us that To convert a tuple to List we can use this process variable_name = list(tuple_variable_name) but implementing this process to my sample code doesn't work BTW I am getting the input using sys.stdin.read()

Here is my code which I am trying to run in my Pycharm

import sys,ast
input_str = sys.stdin.read()
input_list = ast.literal_eval(input_str)

def my_sort(a1):
    a = list(a1)
    for i in a:
        if (a[i]%5) < (a[i+1]% 5):
            temp = a[i]
            a[i] = a[i+1]
            a[i+1] = temp
    print(a)

my_sort(input_list)

Can anyone help me in clearing out my doubts or Understanding These Concepts

Answer 1

I thought it might be worth posting a simple, complete example, since the discussion in the comments lead to a bunch of new information which isn't obvious in the post.

#str_in = input('Enter the numbers to sort: ')
str_in = '1,9,35,12,13,21,10'

nums = [int(elem) for elem in str_in.split(',')]

sorted_nums = sorted(nums, key=lambda x: x % 5)

print(sorted_nums)

Output:

[35, 10, 1, 21, 12, 13, 9]

Answer 2

Change for i in a to for i in range(len(a)) :

import sys,ast
input_str = sys.stdin.read()
input_list = ast.literal_eval(input_str)

def my_sort(a1):
    a = list(a1)
    for i in range(len(a)):
        if (a[i]%5) < (a[i+1]% 5):
            temp = a[i]
            a[i] = a[i+1]
            a[i+1] = temp
    print(a)

my_sort(input_list)

for i in a loops over each element in a while for i in range(len(a)) loops over each index.