使用 .equals (Java) 遍历一个字符串并将结果与​​另一个字符串进行比较

Question

import java.util.Scanner;

public class Main {

    public static void main(String[] args){

        Landscape landscape = new Landscape();

        Scanner keyboardScanner = new Scanner(System.in);

        System.out.println("Enter your terrain: ");

        String TerrainInput = keyboardScanner.nextLine();

        for (int i = 0; i < TerrainInput.length(); i++){

            char j = TerrainInput.charAt(i);

            if j.**equals(**"m") {
                //landscape.mountain(int [j+1])
            }

            if j.**equals**("f"){
                //landscape.flat(int [j+1])
            }
            if j.**equals**("h"){
                //landscape.hill(int [j+1])
            }
        }

    landscape.print();

The program should receive some input string like f3,m3,f2,m0,f4,h1,f1 my plan is to iterate through each character and check if it is equal "f,m, or h" and if it is then i will call the appropriate method and use the number after "f,m, or h" as an argument by calling the method with the index of the letter character found + 1.

for (int i = 0; i < TerrainInput.length(); i++){
    char j = TerrainInput.charAt(i);

    if j.**equals(**"m") {
        //landscape.mountain(int [j+1])
    }
}

The issue is the .equals isn't working, its saying Cannot resolve method 'equals(java.lang.String)'

Answer 1

j is a char, not a String. Chars are compared using == , not equals

if (j == 'm')

Answer 2

Java is different than Python and JavaScript. charAt doesn't return a String , it returns a char (exclusively a character). Therefore you can't compare it to a String . If you write a character in single quotes, that will be a char like this: 'a' . Also, char is a primitive type, so you can compare with == .