从列表字典中获取一组唯一值

Question

I have a list of dictionaries.I want to generate a set of the values of the respective nested lists so that I end up with a set of all of the unique items (in this case, "date" and "sicil").

a=[{'id': 709560, 'date': '27.11.2019', 'sicil': '3119', 'uretimSuresiMakina': 445, 'normalizeCycleTime': 1.0},
     {'id': 709561, 'date': '27.11.2019', 'sicil': '3430', 'uretimSuresiMakina': 445, 'normalizeCycleTime': 1.0},
     {'id': 709562, 'date': '27.11.2019', 'sicil': '3119', 'uretimSuresiMakina': 445, 'normalizeCycleTime': 1.0}, 
     {'id': 709563, 'date': '28.11.2019', 'sicil': '3430', 'uretimSuresiMakina': 385, 'normalizeCycleTime': 0.998271392},
     {'id': 709568, 'date': '28.11.2019', 'sicil': '3119', 'uretimSuresiMakina': 445, 'normalizeCycleTime': 1.0},
     {'id': 709569, 'date': '02.12.2019', 'sicil': '3119', 'uretimSuresiMakina': 445, 'normalizeCycleTime': 1.0}, 
     {'id': 709570, 'date': '02.12.2019', 'sicil': '3430', 'uretimSuresiMakina': 445, 'normalizeCycleTime': 1.0},
     {'id': 709571, 'date': '02.12.2019', 'sicil': '3119', 'uretimSuresiMakina': 445, 'normalizeCycleTime': 1.0},
     {'id': 709575, 'date': '03.12.2019', 'sicil': '3119', 'uretimSuresiMakina': 385, 'normalizeCycleTime': 0.998271392},
     {'id': 709576, 'date': '03.12.2019', 'sicil': '3430', 'uretimSuresiMakina': 355, 'normalizeCycleTime': 0.997191011},
     {'id': 709577, 'date': '03.12.2019', 'sicil': '3119', 'uretimSuresiMakina': 385, 'normalizeCycleTime': 0.998271392}, 
     {'id': 709585, 'date': '04.12.2019', 'sicil': '3119', 'uretimSuresiMakina': 445, 'normalizeCycleTime': 1.0},
     {'id': 709586, 'date': '04.12.2019', 'sicil': '3430', 'uretimSuresiMakina': 445, 'normalizeCycleTime': 1.0}]

I want to create for dates:

unique_dates={'27.11.2019', '28.11.2019', '02.12.2019', '03.12.2019', '04.12.2019'}

Answer 1

Try the code below ,

a=[{'id': 709560, 'date': '27.11.2019', 'sicil': '3119', 'uretimSuresiMakina': 445, 'normalizeCycleTime': 1.0},
     {'id': 709561, 'date': '27.11.2019', 'sicil': '3430', 'uretimSuresiMakina': 445, 'normalizeCycleTime': 1.0},
     {'id': 709562, 'date': '27.11.2019', 'sicil': '3119', 'uretimSuresiMakina': 445, 'normalizeCycleTime': 1.0}, 
     {'id': 709563, 'date': '28.11.2019', 'sicil': '3430', 'uretimSuresiMakina': 385, 'normalizeCycleTime': 0.998271392},
     {'id': 709568, 'date': '28.11.2019', 'sicil': '3119', 'uretimSuresiMakina': 445, 'normalizeCycleTime': 1.0},
     {'id': 709569, 'date': '02.12.2019', 'sicil': '3119', 'uretimSuresiMakina': 445, 'normalizeCycleTime': 1.0}, 
     {'id': 709570, 'date': '02.12.2019', 'sicil': '3430', 'uretimSuresiMakina': 445, 'normalizeCycleTime': 1.0},
     {'id': 709571, 'date': '02.12.2019', 'sicil': '3119', 'uretimSuresiMakina': 445, 'normalizeCycleTime': 1.0},
     {'id': 709575, 'date': '03.12.2019', 'sicil': '3119', 'uretimSuresiMakina': 385, 'normalizeCycleTime': 0.998271392},
     {'id': 709576, 'date': '03.12.2019', 'sicil': '3430', 'uretimSuresiMakina': 355, 'normalizeCycleTime': 0.997191011},
     {'id': 709577, 'date': '03.12.2019', 'sicil': '3119', 'uretimSuresiMakina': 385, 'normalizeCycleTime': 0.998271392}, 
     {'id': 709585, 'date': '04.12.2019', 'sicil': '3119', 'uretimSuresiMakina': 445, 'normalizeCycleTime': 1.0},
     {'id': 709586, 'date': '04.12.2019', 'sicil': '3430', 'uretimSuresiMakina': 445, 'normalizeCycleTime': 1.0}]

set(d['date'] for d in a)

output

{'02.12.2019', '03.12.2019', '04.12.2019', '27.11.2019', '28.11.2019'}

Answer 2

{dict['date'] for dict in a}

这将从发出键值的集合理解中创建一个集合（这是一个唯一的值列表）：'date'