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按列名拆分数据帧中的多索引数据帧

[英]Split a multi-index dataframe in dataframes by column names

I have a dataframe like the following: Multi-index dataframe by columns我有一个如下所示的数据框:按列的多索引数据框

I would like to get 3 dataframes named like each columns (compass, accel, gyro) with the timeindex untouched, and three columns each(df1, df2, df3).我想获得 3 个数据帧,命名为每列(指南针、加速、陀螺仪),时间索引未受影响,每列三列(df1、df2、df3)。

I've tried for index,row in df.iterrows(): but couldnt really got it to work And I was thinking in somenthing stack() and unstack() but don't really know how.我已经尝试for index,row in df.iterrows():但无法真正让它工作而且我在想stack()和 unstack unstack()但真的不知道如何。

You can save the 3 first columns in a csv file, and repeat the process more 2 times to the others csv files...您可以将前 3 列保存在 csv 文件中,然后对其他 csv 文件重复该过程 2 次...

You can select the 3 columns to your dataframe like this:您可以像这样选择数据框的 3 列:

x = 0
data=pd.read_csv(file.csv, keep_default_na=False, skiprows=line_header, na_filter=False, usecols=[x,x+1,x+2])[[compass, accel, gyro]])

where x = your first column of the "big dataframe"其中 x = “大数据框”的第一列

the usecols property is really useful in this case在这种情况下 usecols 属性非常有用

You can read more about in: Pandas.read_csv您可以在以下位置阅读更多信息: Pandas.read_csv

groupby allows you to split the DataFrame along a MultiIndex level with the same level_values. groupby允许您沿具有相同 level_values 的 MultiIndex 级别拆分 DataFrame。 We will use DataFrame.xs to remove the grouping Index level, leaving you with only the columns you care about.我们将使用DataFrame.xs删除分组索引级别,只留下您关心的列。 Separate DataFrames are stored in a dictionary, keyed by the unique level-1 values of the original column MultiIndex.单独的 DataFrame 存储在字典中,由原始列 MultiIndex 的唯一级别 1 值键控。

Sample Data样本数据

import pandas as pd
import numpy as np
np.random.seed(123)
df = pd.DataFrame(np.random.randint(1, 10, (4, 9)),
                  columns=pd.MultiIndex.from_product([['df1', 'df2', 'df3'],
                                                      ['compass', 'gyro', 'accel']]))
#      df1                df2                df3           
#  compass gyro accel compass gyro accel compass gyro accel
#0       3    3     7       2    4     7       2    1     2
#1       1    1     4       5    1     1       5    2     8
#2       4    3     5       8    3     5       9    1     8
#3       4    5     7       2    6     7       3    2     9

Code代码

d = {idx: gp.xs(idx, level=1, axis=1) for idx,gp in df.groupby(level=1, axis=1)}
d['gyro']
#   df1  df2  df3
#0    3    4    1
#1    1    1    2
#2    3    3    1
#3    5    6    2

As such splits are readily available with a groupby you may not even need to store the separate DataFrames;由于这样的拆分可以通过groupby轻松获得,您甚至可能不需要存储单独的 DataFrame; you can manipulate each of them separately with GroupBy.apply .您可以使用GroupBy.apply分别操作它们中的每一个。

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