查找对象数组中的计数总数

Question

Include how many of the potential voters were in the ages 18-25, how many from 26-35, how many from 36-55, and how many of each of those age ranges actually voted. The resulting object containing this data should have 6 properties.

var voters = [
    {name:'Bob' , age: 30, voted: true},
    {name:'Jake' , age: 32, voted: true},
    {name:'Kate' , age: 25, voted: false},
    {name:'Sam' , age: 20, voted: false},
    {name:'Phil' , age: 21, voted: true},
    {name:'Ed' , age:55, voted:true},
    {name:'Tami' , age: 54, voted:true},
    {name: 'Mary', age: 31, voted: false},
    {name: 'Becky', age: 43, voted: false},
    {name: 'Joey', age: 41, voted: true},
    {name: 'Jeff', age: 30, voted: true},
    {name: 'Zack', age: 19, voted: false}
];

function voterResults(arr) {
   // your code here
}

console.log(voterResults(voters)); // Returned value shown below:
/*
{ youngVotes: 1,
  youth: 4,
  midVotes: 3,
  mids: 4,
  oldVotes: 3,
  olds: 4 
}

I am being trying out this specific problem, below is what I have tried, where i am able to form the hashmap. But not sure how I can solve the above problem.

function voterResults(arr) {
  let votesArray = ['youngVotes', 'youth', 'midVotes', 'mids', 
      'oldVotes', 'olds']
   return votesArray.reduce((acc, it) => {
     acc[it] = (acc[it] || 0) + 1  
     return acc;
   }, {})
}

//output

{
   youngVotes: 1 ,
   youth: 1 ,
   midVotes: 1 ,
   mids: 1 ,
   oldVotes: 1 ,
   olds: 1
}

Actual output needed:

{
  youngVotes: 1,
  youth: 4,
  midVotes: 3,
  mids: 4,
  oldVotes: 3,
  olds: 4 
}

Answer 1

I'd first make a helper function that returns the property strings corresponding to the age passed (eg 20 -> ['youth', 'youngVotes'] ). Then use .reduce to iterate over the voters array - call that function to find out which property to increment, and increment it:

 const getCat = (age) => { if (age < 25) return ['youth', 'youngVotes']; if (age < 35) return ['mids', 'midVotes']; return ['olds', 'oldVotes']; }; var voters = [ {name:'Bob' , age: 30, voted: true}, {name:'Jake' , age: 32, voted: true}, {name:'Kate' , age: 25, voted: false}, {name:'Sam' , age: 20, voted: false}, {name:'Phil' , age: 21, voted: true}, {name:'Ed' , age:55, voted:true}, {name:'Tami' , age: 54, voted:true}, {name: 'Mary', age: 31, voted: false}, {name: 'Becky', age: 43, voted: false}, {name: 'Joey', age: 41, voted: true}, {name: 'Jeff', age: 30, voted: true}, {name: 'Zack', age: 19, voted: false} ]; const counts = voters.reduce((a, { age, voted }) => { const [prop, voteProp] = getCat(age); a[prop] = (a[prop] || 0) + 1; if (voted) { a[voteProp] = (a[voteProp] || 0) + 1; } return a; }, {}); console.log(counts);

Answer 2

You need to use input arr, and use-value of voted and use age to classify and increment value in the object.

const voters = [
    {name:'Bob' , age: 30, voted: true},
    {name:'Jake' , age: 32, voted: true},
    {name:'Kate' , age: 25, voted: false},
    {name:'Sam' , age: 20, voted: false},
    {name:'Phil' , age: 21, voted: true},
    {name:'Ed' , age:55, voted:true},
    {name:'Tami' , age: 54, voted:true},
    {name: 'Mary', age: 31, voted: false},
    {name: 'Becky', age: 43, voted: false},
    {name: 'Joey', age: 41, voted: true},
    {name: 'Jeff', age: 30, voted: true},
    {name: 'Zack', age: 19, voted: false}
];

// define your limit here, will check for <= of defined age
let categories = { youngVotes: 21, youth: 30, midVotes: 40, mids: 50, oldVotes: 60, olds: 130}

function voterResults(arr) {
const conditions = Object.entries(categories);
   return arr.reduce((val, vote)=>{
        if(vote.voted) {

        for(let i=0;i<conditions.length;i++) {
            if(vote.age <= conditions[i][1]) {
            val[conditions[i][0]] = val[conditions[i][0]] ? val[conditions[i][0]] + 1 : 1;
            return val;
          }
        }
      }
      return val;
   }, {})
}

console.log(voterResults(voters));

Answer 3

Here is using reduce method and age groups can be extended easily.

 function voterResults(arr) { const ranges = { youngVotes: [18, 25], youth: [26, 35] }; return arr .filter(x => x.voted) .reduce((acc, curr) => { Object.keys(ranges).forEach(key => { if (curr.age >= ranges[key][0] && curr.age <= ranges[key][1]) { acc[key] = key in acc ? acc[key] + 1 : 1; } }); return acc; }, {}); } var voters = [ { name: "Bob", age: 30, voted: true }, { name: "Jake", age: 32, voted: true }, { name: "Kate", age: 25, voted: false }, { name: "Sam", age: 20, voted: false }, { name: "Phil", age: 21, voted: true }, { name: "Ed", age: 55, voted: true }, { name: "Tami", age: 54, voted: true }, { name: "Mary", age: 31, voted: false }, { name: "Becky", age: 43, voted: false }, { name: "Joey", age: 41, voted: true }, { name: "Jeff", age: 30, voted: true }, { name: "Zack", age: 19, voted: false } ]; console.log(voterResults(voters));

Answer 4

You can do simply using if conditions

var voters = [
    {name:'Bob' , age: 30, voted: true},
    {name:'Jake' , age: 32, voted: true},
    {name:'Kate' , age: 25, voted: false},
    {name:'Sam' , age: 20, voted: false},
    {name:'Phil' , age: 21, voted: true},
    {name:'Ed' , age:55, voted:true},
    {name:'Tami' , age: 54, voted:true},
    {name: 'Mary', age: 31, voted: false},
    {name: 'Becky', age: 43, voted: false},
    {name: 'Joey', age: 41, voted: true},
    {name: 'Jeff', age: 30, voted: true},
    {name: 'Zack', age: 19, voted: false}
];


function voterResults(){
    let youngVotes = 0;
    let youth = 0;
    let midVotes = 0;
    let mids =0;
    let oldVotes =0;
    let olds =0;
    for (var i = voters.length - 1; i >= 0; i--) {
        if(voters[i].age >= 18 && voters[i].age <= 25 && voters[i].voted === true){
            youngVotes++;
        }
        if(voters[i].age >= 18 && voters[i].age <= 25){
            youth++;
        }
        if(voters[i].age >= 26 && voters[i].age <= 35 && voters[i].voted === true){
            midVotes++;
        }
        if(voters[i].age >= 26 && voters[i].age <= 35 ){
            mids++;
        }
        if(voters[i].age >= 36 && voters[i].age <= 55 && voters[i].voted === true){
            oldVotes++;
        }
        if(voters[i].age >= 36 && voters[i].age <= 55){
            olds++;
        }
    }

    return{
        youngVotes,
        youth,
        midVotes,
        mids,
        oldVotes,
        olds
    }

}
console.log(voterResults())