在 Javascript 中查找值的乘积

Question

Write a function called productOfValues which takes in an object of key/value pairs and multiplies the values together. You can assume that all keys are strings and all values are integers.

For example:

let testObject = {
  'a': 5, 
  'b': 12,
  'c': 3
}

productOfValues(testObject)

So, this is what I wrote:

 let testObject = { 'a': 5, 'b': 12, 'c': 3, 'd': 1 } let testObject_v = { 'z': 2, 'y': 2, 'x': 2, 'w': 2 } function productOfValues(someObject) { return someObject.a * someObject.b * someObject.c; } function productOfValues(testObject) { return testObject_v.z * testObject_v.y * testObject_v.x * testObject_v.w; } console.log(productOfValues(testObject)) console.log(productOfValues(testObject_v))

And I've got an error of:

Your productOfValues function should return the product of the values in the given object: 180

Answer 1

You can use Object.values to convert your object to array of its values & then use reduce to get the product of that values array

 let testObject = {'a': 5,'b': 12,'c': 3, 'd':1}; let testObject_v = { 'z':2,'y':2,'x':2,'w':2 } function productOfValues(someObject) { return Object.values(someObject).reduce((a,b)=> a*b ,1); } console.log(productOfValues(testObject)); console.log(productOfValues(testObject_v));

Answer 2

You're defining the same function twice and you're only multiplying the first 3 numbers in the first object. Instead, rewrite your productOfValues() function to be something like this:

 let testObject = { 'a': 5, 'b': 12, 'c': 3, 'd': 1 } let testObject_v = { 'z': 2, 'y': 2, 'x': 2, 'w': 2 } function productOfValues(someObject) { let product = 1; for (const i in someObject) { product = product * someObject[i]; } return product; } console.log(productOfValues(testObject)) console.log(productOfValues(testObject_v))

Edit: Alternative productOfValues() function:

function productOfValues(someObject) {
  var result = 1; 
  var len = Object.keys(someObject).length; 
  for (var i = 0; i < len; i++) {     
    result = result * someObject[Object.keys(someObject)[i]]; 
  }
  return result;
}