使用 str.contains 后合并两个数据框？

Question

I have two data frames I want to match partial strings by using str.contains function then merge them.

Here is an example:

data1

      email     is_mane         name           id
    hi@amal.com     1   there is rain          10
    hi2@amal.com    1   here is the food        9
    hi3@amal.com    1   let's go together       8
    hi4@amal.com    1   today is my birthday    6


data2

    id  name
    1   the rain is beautiful
    1   the food
    2   together
    4   my birthday
    3   your birthday

And here is the code I wrote:

data.loc[data.name.str.contains('|'.join(data2.name)),:]

and the output:

        email   is_mane     name               id
    hi2@amal.com    1   here is the food        9
    hi3@amal.com    1   let's go together       8
    hi4@amal.com    1   today is my birthday    6

As you can see it did not return "there is rain" even that rain word is contained in dara2 : could it be because of space?

Also I want to merge data1 with data2 so that will help me to know what email has match.

I would like to have the following output:

        email   is_mane     name               id      id2       name2
    hi2@amal.com    1   here is the food        9       1       the food
    hi3@amal.com    1   let's go together       8       2       together
    hi4@amal.com    1   today is my birthday    6       4       my birthday
    hi4@amal.com    1   today is my birthday    6       3       your birthday

Is there is any way to do it?

Answer 1

If you're good with matching only full words you can do (so eg dog and dogs won't match)

data1["key"]=data1["name"].str.split(r"[^\w+]")
data2["key"]=data2["name"].str.split(r"[^\w+]")

data3=data1.explode("key").merge(data2.explode("key"), on="key", suffixes=["", "2"]).drop("key", axis=1).drop_duplicates()

Otherwise it's a matter of cross join, and applying str.contains(...) to filter out the ones, which aren't matching.