[英]Cannot understand how to write a testcase for weekdays in python using unittest module
I have a function in python which takes weekday as a parameter and returns an int on successfull weekday, im a newbie in python unittesting and i wish to know how to write the unittest case for the same.我在python中有一个函数,它将工作日作为参数并在工作日成功返回一个int,我是python单元测试的新手,我想知道如何编写单元测试用例。 here's the function:这是功能:
def dayNameFromWeekday(weekday):
if weekday == "Monday":
return 0
if weekday == "Tuesday":
return 1
if weekday == "Wednesday":
return 2
if weekday == "Thursday":
return 3
if weekday == "Friday":
return 4
if weekday == "Saturday":
return 5
if weekday == "Sunday":
return 6
and here's the testfile这是测试文件
class Utils(unittest.TestCase):
def test_dayNameFromWeekday(self, weekday):
if weekday == "Monday":
return 0
elif weekday == "Tuesday":
return 1
elif weekday == "Wednesday":
return 2
elif weekday == "Thursday":
return 3
elif weekday == "Friday":
return 4
elif weekday == "Saturday":
return 5
elif weekday == "Sunday":
return 6
else:
return -1 # Any error message
res = self.test_dayNameFromWeekday("Monday")
and i have no idea how to write a test case for this function, please enlighten me with the way the things are done in unittest python..我不知道如何为这个函数编写一个测试用例,请教我在 unittest python 中完成这些事情的方式..
Here is the solution:这是解决方案:
import unittest
class Utils(unittest.TestCase):
def test_dayNameFromWeekday(self, weekday):
if weekday == "Monday":
return 0
elif weekday == "Tuesday":
return 1
elif weekday == "Wednesday":
return 2
elif weekday == "Thursday":
return 3
elif weekday == "Friday":
return 4
elif weekday == "Saturday":
return 5
elif weekday == "Sunday":
return 6
else:
return -1 # Any error message
def runTest(self):
res = self.test_dayNameFromWeekday("Monday")
print(res)
res = Utils()
res.run()
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