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使用nodejs从多个集合中获取mongodb集合记录

[英]fetching mongodb collection records from multiple collections using nodejs

below is all the description collection 1 : users以下是所有描述集合1:用户

"_id" : ObjectId("5e2977e1cc1208c65c00648b"),
        "mappedShops" : [
                ObjectId("5e2976cbcc1208c65c006488"),
                ObjectId("5e2976cbcc1208c65c00690c"),
                ObjectId("5e2976cbcc1208c65c006499")
       "phoneNo" : 6789012345,
        "name" : "acdbcs",
        "address" : "address 2",
        "shopCode" : "D3137",
        "state" : "M.P",
        "city" : "Indore"

NOTE : deatils of mappedShops for eg: ObjectId("5e2976cbcc1208c65c00690c") is in the same users collection注意mappedShops 的详细信息,例如:ObjectId("5e2976cbcc1208c65c00690c") 在同一个用户集合中
collection 2 : orders系列 2 : 订单

"_id" : ObjectId("5e27f998a42d441fe8a8957f"),
        "isApproved" : false,
"orderCreatedOn" : ISODate("2020-01-22T18:30:00Z"),
"shopOrder" : [],
"frequency" : "WE",
"orderCreatedBy" : ObjectId("5e2976cbcc1208c65c00690c")

Collection 3: payments集合 3:付款

 "_id" :  ObjectId("5dd7900bcd00d33c245abbfa"),
 "paymentOfTheDay" : 400,
 "outstanding" : 100,
 "paymentDoneBy":ObjectId("5e2976cbcc1208c65c00690c")

scenario is : i will get _id(ie admin id) from req.body Here is what i need to do 1: i need to know all the mappedShops objectId's & than for all those objectId's i need to find the details of all those objectId's 2: than i need to look what order that shop has created from order collection.(for all those id's) 3: than i need to look what is the outstanding from the payments collection(again for all the id's) Here is what i need to send to the frontend in the mentioned object Array {"name","phoneNo","address"}(from users collection)+{"orderCreatedOn": ISODate("2020-01-22T18:30:00Z"),"isApproved"}(from orders collection)+{"outstanding"}(from payments collection) expected response may look like this:场景是:我将从 req.body 获取 _id(即管理员 ID)这是我需要做的1:我需要知道所有映射商店的 objectId 和所有那些 objectId 我需要找到所有这些 objectId 的详细信息 2 :比我需要查看商店从订单集合中创建的订单。(对于所有这些 ID) 3:比我需要查看付款集合中的未付款项(再次对于所有 ID)这是我需要的发送到提到的对象数组中的前端{"name","phoneNo","address"}(from users collection)+{"orderCreatedOn": ISODate("2020-01-22T18:30:00Z"),"isApproved "}(来自订单收款)+{"outstanding"}(来自付款收款)预期响应可能如下所示:

"shopsListDetails":[{
"phoneNo","name","address","shopCode" ,"isApproved","outstanding"
}]

POSTMAN REQUEST this is the id of admin POSTMAN REQUEST这是管理员的 id

{
    "_id": "5e2977e1cc1208c65c00648b"
}

ultimately front end shall receive all the data which i mentioned in shopsListDetails[{}] for all the mappedShops in the user collection against that admin I am kind of very much stuck in this if any can help me out最终前端将收到我在shopsListDetails[{}] 中提到的所有数据,用于针对该管理员的用户集合中的所有mappedShops,如果有任何可以帮助我的话我非常陷入困境

Considering the first schema you shared is of User考虑到您共享的第一个架构是User

I am assuming You are storing order_id inside payments Schemama我假设您正在payments Schemama 中存储order_id

You can write aggregate query like this您可以像这样编写聚合查询

    User.aggregate([
        {
            $match:{
                _id:req.body.admin_id
            }
        },{
            $unwind:'$mappedShops'
        },{
            $lookup:{
                from:'users',
                localField:'mappedShops',
                foreignField:'_',
                as:'mappedShops'
            }
        },{
            $unwind:'$mappedShops'
        },{
            $lookup:{
                from:'orders',
                localField:'mappedShops._id',
                foreignField:'orderCreatedBy',
                as:'order'
            }
        },{
            $unwind:'$order'
        },{
            $lookup:{
                from:'payments',
                localField:'order._id',
                foreignField:'order_id',
                as:'payment'
            }
        },{
            $unwind:'$payment'
        },{
            $project:{
                _id:0,
                name:'$mappedShops.name',
                phoneNo:'$mappedShops.phoneNo',
                address:'$mappedShops.address',
                orderCreatedOn:'$order.orderCreatedOn',
                isApproved:'$order.isApproved',
                outstanding:'$payment.outstanding'
            }
        }
    ])
  1. Firstly, we unwind all the mappedShops & get individual objects of the same from Lookups |首先,我们展开所有映射的商店并从 Lookups | 中获取相同的单个对象。 This gives us the User details for final data这为我们提供了最终数据的用户详细信息
  2. Then, we find matching order for each mappedshops from orders collection by $lookup & $unwind same |然后,我们通过$lookup$unwind same | 从orders集合中找到每个mappedshops匹配订单。 This gives us the order details for final data这为我们提供了最终数据的订单详细信息
  3. Lastly, We match order_id inside payments collection through $lookup & get payment status of each order |最后,我们通过$lookup匹配付款集合中的order_id并获取每个订单的付款状态 | This gives us the payment status for final data这为我们提供了最终数据的付款状态

PS : For this to worker, you must have the entry of each order in both orders & payments collection, whether or not payment is completed PS:对于这个工作人员,您必须在orderspayments收集中输入每个orders ,无论付款是否完成

Comment below if you need more clarification / any change is needed here如果您需要更多说明/此处需要任何更改,请在下面发表评论

Please try this :请试试这个:

db.users.aggregate([
    {
        $match: {
            _id: req.body.adminID
        }
    }, {
        $lookup: {
            from: 'users',
            localField: 'mappedShops',
            foreignField: '_id',
            as: 'mappedShops'
        }
    }, { $unwind: '$mappedShops'}, { $replaceRoot: { newRoot: "$mappedShops" } },
    { 
       $lookup:
        {
            from: "orders",
            let: { mappedShopsId: "$_id" },
            pipeline: [
                {
                    $match: { $expr: { $eq: ["$orderCreatedBy", "$$mappedShopsId"] } }
                },
                { $project: { orderCreatedOn: 1, isApproved: 1 } }
            ],
            as: "orders"
        }
    },{
       $lookup:
        {
            from: "payments",
            let: { mappedShopsId: "$_id" },
            pipeline: [
                {
                    $match: { $expr: { $eq: ["$paymentDoneBy", "$$mappedShopsId"] } }
                },
                { $project: { outstanding: 1 } }
            ],
            as: "payments"
        }
    },
    { $project: { name: 1, phoneNo: 1, address: 1, shopCode: 1, orders: 1, payments: 1 } }
])

Test : MongoDB-Playground测试: MongoDB-Playground

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