[英]xslt: conditional update on following sibling based on current node
I have XML file like this:我有这样的 XML 文件:
<?xml version="1.0" encoding="UTF-8"?>
<Root>
<Data>
<D1_01>23</D1_01>
<D1_03>2</D01_03>
<D1_04>9</D01_04>
<Record>
<R9>
<R9_01>-5</R9_01>
<R9_02>-5</R9_02>
<R9_05>XSLT Document Function1</R9_05>
<R9_11>-5</R9_11>
</R9>
<S>
<S_01>CC= </S_01>
</S>
</Record>
<Record>
<R9>
<R9_01>-5</R9_01>
<R9_02>-5</R9_02>
<R9_05>XSLT Document Function2</R9_05>
<R9_11>-5</R9_11>
</R9>
<S>
<S_01>CC= </S_01>
</S>
</Record>
.
.
.
</Data>
</Root>"
For each Record check (string-length(R9_05) > 10),if it is true then change the text of R9_05 as 'Reference' and append the text of R9_05 to the following-sibling S_01.对于每个记录检查(字符串长度(R9_05)> 10),如果为真,则将 R9_05 的文本更改为“参考”并将 R9_05 的文本附加到以下兄弟 S_01。
Desired output is:期望的输出是:
<?xml version="1.0" encoding="UTF-8"?>
<Root>
<Data>
<D1_01>23</D1_01>
<D1_03>2</D01_03>
<D1_08>8</D1_08>
<Record>
<R9>
<R9_01>-5</R9_01>
<R9_02>-5</R9_02>
<R9_05>Reference</R9_05>
<R9_11>-5</R9_11>
</R9>
<S>
<S_01>CC=XSLT Document Function1 </S_01>
</S>
</Record>
<Record>
<R9>
<R9_01>-5</R9_01>
<R9_02>-5</R9_02>
<R9_05>Reference</R9_05>
<R9_11>-5</R9_11>
</R9>
<S>
<S_01>CC=XSLT Document Function2 </S_01>
</S>
</Record>
.
.
.
</Data>
</Root>
Below is my XSLT code:下面是我的 XSLT 代码:
<xsl:template match="Root/Data">
<xsl:for-each select="Record">
<xsl:variable name="var_R9_05">
<xsl:choose>
<xsl:when test="string-length(R9/R9_05) > 10">
<xsl:value-of select="concat(following-sibling::S/S_01, ' ', R9_05)"/>
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="//S_01"/>
</xsl:otherwise>
</xsl:choose>
</xsl:variable>
<xsl:element name="R9_05"> "See narrative for complaint" </xsl:element>
<xsl:element name="S_01">
<xsl:call-template name="value-to-replace">
<xsl:with-param name="param.str" select="following-sibling::S"/>
<xsl:with-param name="param.target" select="following-sibling::S/S_01"/>
<xsl:with-param name="param.replacement" select="$var_R9_05)"/>
</xsl:call-template>
</xsl:element>
</xsl:for-each>
</xsl:template>
Not getting desired output, I am new to XSLT and XML, Can someone please help me?没有得到想要的输出,我是 XSLT 和 XML 的新手,有人可以帮我吗?
How about:怎么样:
XSLT 1.0 XSLT 1.0
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<!-- identity transform -->
<xsl:template match="@*|node()">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="R9_05[string-length(.) > 10]">
<R9_05>Reference</R9_05>
</xsl:template>
<xsl:template match="S_01/text()">
<xsl:copy/>
<xsl:value-of select="../../../R9/R9_05[string-length(.) > 10]"/>
</xsl:template>
</xsl:stylesheet>
This could be improved so that the test is performed only once.这可以改进,以便测试只执行一次。
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