[英]Setting the color of a shape programmatically
I am trying to set the color of my shape programmatically, inside my drawable I created a rounded shape (rounded_button.xml):我试图以编程方式设置我的形状的颜色,在我的 drawable 中,我创建了一个圆形(rounded_button.xml):
<?xml version="1.0" encoding="utf-8"?>
<shape xmlns:android="http://schemas.android.com/apk/res/android"
android:shape="rectangle">
<solid android:color="#00b248" />
<corners android:bottomRightRadius="8dp"
android:bottomLeftRadius="8dp"
android:topRightRadius="8dp"
android:topLeftRadius="8dp"/>
</shape>
And now I want to change it color in my activity.现在我想在我的活动中改变它的颜色。
public void setShapeColor() {
Drawable shapeDrawable = ResourcesCompat.getDrawable(getResources(), R.drawable.rounded_button, null);
shapeDrawable.setColorFilter(Color.WHITE, PorterDuff.Mode.SRC_ATOP);
}
But it does not work and holds still the same color.但它不起作用并且仍然保持相同的颜色。
This how you can change color defined drawable in xml这是如何更改 xml 中定义的可绘制颜色的方法
LayerDrawable shapeRectangle = (LayerDrawable) getDrawable(context, R.drawable.custom_layer);
GradientDrawable gradient = (GradientDrawable) shapeRectangle.findDrawableByLayerId(R.id.shape_rectangle);
gradient.setColor(Color.RED);
Try to use tint to made tint of drawable.尝试使用 tint 使可绘制的色调。
example:例子:
fun getTintDrawable(context:Context, resId: Int, tint: Int): Drawable? {
val normalDrawable = ContextCompat.getDrawable(context, resId)
var wrapDrawable = if (normalDrawable == null) null else DrawableCompat.wrap(normalDrawable)
if (wrapDrawable != null) {
DrawableCompat.setTint(wrapDrawable, tint)
}
return wrapDrawable
}
Sorry that i use kotlin, but rewrite to java could not take so much time.抱歉,我使用 kotlin,但重写为 java 不会花费太多时间。 Hope it helps.希望能帮助到你。
BR BR
@Nullable
public Drawable getTintDrawable(Context context, int resId, int tint) {
Drawable normalDrawable = ContextCompat.getDrawable(context, resId);
Drawable wrapDrawable = (normalDrawable == null) ? null : DrawableCompat.wrap(normalDrawable);
if (wrapDrawable != null) {
DrawableCompat.setTint(wrapDrawable, tint);
}
return wrapDrawable;
}
As requested by @Jonnotdoexx根据@Jonnotdoexx 的要求
Same code in Java: Java中的相同代码:
Please note that this function will return null if first if
clause fail to execute.请注意,如果第一个if
子句执行失败,此函数将返回 null。
Drawable getTintDrawable(Context context, int resId, int tint) {
Drawable normalDrawable = ContextCompat.getDrawable(context, resId);
Drawable wrapDrawable;
if (normalDrawable != null)
wrapDrawble = DrawableCompat.wrap(normalDrawable);
if (wrapDrawable != null)
DrawableCompat.setTint(wrapDrawable, tint);
return wrapDrawable;
}
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