[英]Array Index Out Of Bounds - Java Recursive Method
I am writing a program with 3 different methods to practice recursion.我正在用 3 种不同的方法编写一个程序来练习递归。 I have successfully implemented one of three, but I am a little stuck on the second right now.
我已经成功实施了三个中的一个,但我现在有点卡在第二个上。 This method attempts to count the number of "smiles" (:)) in a character array.
此方法尝试计算字符数组中“微笑”(:)) 的数量。 I thought I had it written correctly but when I test it out I keep getting an ArrayIndexOutOfBoundsException, but I'm not sure why.
我以为我写对了,但是当我测试它时,我不断收到 ArrayIndexOutOfBoundsException,但我不知道为什么。 My method is as follows:
我的方法如下:
public static int countSmiles(char[] letters, int index) {
int smileCounter = 0;
//If the array is less than 2 in length it cannot include ":)".
if(letters.length < 2) {
return 0;
}
//If there is a smile increment the counter.
else if(letters[index] == ':') {
if(letters[index+1] == ')') {
smileCounter++;
}
}
//Increment the index
index++;
//Recursive assignment
smileCounter = countSmiles(letters, index);
//Return number of smiles
return smileCounter;
}
And the method I am testing with is as follows:我正在测试的方法如下:
public static void main(String[] args) {
char[] JavaCharArray = {'r', 's', 't', 'u', ':', ')', 'v'};
System.out.println(countSmiles(JavaCharArray, 0));
}
From my code it doesn't seem that the index I am trying to access (0) is negative nor greater than the provided array.从我的代码看来,我试图访问的索引 (0) 不是负数,也不是大于提供的数组。 I really just don't understand.
我真的只是不明白。
In a recursive method, you need a stop condition.在递归方法中,您需要一个停止条件。 Try:
尝试:
...
if(letters.length < 2) {
return 0;
}
if (index + 2 > letters.length) {
return 0;
}
...
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