在编译时检查静态函数是否存在

Question

function. c (I can't edit this file)

#define FOO    1

#if FOO == 1
    void Foo() {}
#endif

cpp

class MyClass
{
#if FOO == 1
    void CppFoo()
    {
        Foo();
    }
#endif
}

I want to do the same thing, but without using the define TEST in the main.cpp file

What I want to do:

class MyClass
{
#if (extern "c" Foo() exist)
    void CppFoo()
    {
        Foo();
    }
#endif
}

The CppFoo() method will not have to be declared if the static function Foo() has not been declared.

How can I do this?

Answer 1

You can use a weak attribute, for example:

file ac:

#include <stdio.h>

int foo() __attribute__ ((weak));
int foo() {}

int main(int argc, char** argv)
{
    foo();
}

File bc:

#include <stdio.h>

int foo () {
    printf("Hello Wurld!\n");
}

Now if you do not compile and link bc, then the default (no-op) function foo() is called, otherwise the function foo() from bc