一次打印一个 C 字符串的一个字符

Question

I have a variable: char *string and a for loop with int i=0 to len(string) .

Inside the loop, it prints &string[i] .

Trying to get it to show only a single character, but if I have a string "red", it would print:

red
ed
d

Answer 1

In order to print a character with printf() , you need to use the appropriate format specifier, %c , like this:

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int main(void)
{
  char* string = malloc(sizeof(char) * 16);
  strcpy(string, "red");
  for(size_t i = 0; i < strlen(string); ++i)
  {
    printf("%c\n", string[i]);
  }
  return 0;
}

Output:

r
e
d

As @jonathanLeffler commented, putchar(string[i]); would do the trick as well.

---

In your attempt, what went wrong is this line ^* :

printf("%s\n", &string[i]);

which, because of the format specifier %s for strings, it will print the whole string until its end (NULL terminator is met), starting from the i -the character.

---

_{Reversed engineered from the sample output of yours and post.}