如果两个元素相同，如何替换列表中的两个元素（Python）

Question

I want to replace elements in a list if they coincide in the same list untill there is only an 1 in the list. If I have [1,0,1,0,1], the list becomes [0,0,1,0,0] or something like that, only with an 1... but it doesnt replace elements and it prints the same list...

 import random 

p = float(input("Introduzca probabilidad de transmisión: "))
q = 1 - p
usuarios = ['Usuario1','Usuario2', 'Usuario3', 'Usuario 4', 'Usuario5']
transmisiones = []

for i in usuarios:
    if random.random() < p:
        transmisiones.append(1)
    else:
        transmisiones.append(0)

    print(transmisiones)

    for elemento in transmisiones:
        if elemento == 1 and transmisiones[0:5] == 1:
            transmisiones[elemento] = 0


    print(transmisiones)




    output:

    Introduzca probabilidad de transmisión: 0.6
    [1, 1, 0, 0, 0]
    [1, 1, 0, 0, 0]

Answer 1

you should write like this

idx= -1
for i in range(len(transmisiones)):
        if transmisiones[i] == 1:
            idx = i
        transmisiones[i] = 0

transmisiones[idx] = 1

the idx always keep the last index where the value is equal to 1

if you want all the indices to be saved append them in the a list