以今天为基础日期，然后计算前后5年中第N天的“日-周”

Question

eg:
If N is 13th and the basic date is today then i hope calling some function or view or sp to get 13th day's day-week group count during 5 years before and after

Expected:
If today is 2020-02-03 then the expected data :

dayOfWeek,count
1,16
2,19
3,16
4,19
5,15
6,18
7,17

What i have tried :

declare @now date = '2020-2-3'; 
declare @TheDateBefore5Years date = dateadd(year,-5,@now) 
    ,@TheDateAfter5Years date = dateadd(year,5,@now) 
;
with cte as (
   //....
)
select dayOfWeek,count(1) count
from cte
group by dayOfWeek

Answer 1

Is this what you want?

select datepart(dow, datecol), count(1) count
from t
where datecol >= dateadd(year, -5, '2020-02-03') and
      datecol <= dateadd(year, 5, '2020-02-03')
group by datepart(dow, datecol)