如何确定对象中的任何数组是否有条目

Question

This is unlike most questions, which concern arrays of objects, not objects of arrays. I have a data structure such as the following, and I need to determine if any of the arrays contained by the object contain any values.

All I need is true/false if any of the arrays has at least one value. Please also consider effort in my (self-)answer.

let pendingAdditions = {
  hospitals: ['Silencio Hospital','St Judes'],
  licenses: ['poe-tic license'],
  medschools: []
} 

Answer 1

I found nothing upon googling, maybe that is because the answer is as simple as:

let somePendingAdditions = Object.values(pendingAdditions).some(arr => arr.length);

However there is an alternative solution which is probably not as performant but also has interesting pitfalls possibly worth noting:

somePendingAdditions = 
    Boolean(Array.prototype.concat.apply([], Object.values(pendingAdditions)).length);

The pitfall(s) have to do with passing the correct first argument to apply. Ordinarily this is done with {} or null , but in the first case {} will be an entry in the resulting array; in the case of passing null an error results.

Answer 2

How about Object.values with flat and includes .

 // Check if Object has value as arrays and atleast one value is there. const hasAnyEntry = (items) => Object.values(items).flat().length > 0; const pendingAdditions = { hospitals: ['Silencio Hospital','St Judes'], licenses: ['poe-tic license'], medschools: [] } console.log(hasAnyEntry(pendingAdditions)); console.log(hasAnyEntry({})); // Check if given entry is exist in Object value arrays const hasEntry = (items, entry) => Object.values(items).flat().includes(entry); console.log(hasEntry(pendingAdditions, 'St Judes')); console.log(hasEntry(pendingAdditions, 'Blah'));