[英]Laravel Eloquent model query
I Want To Achieve the right query in laravel if anyone can help如果有人可以提供帮助,我想在 laravel 中实现正确的查询
I have This query我有这个查询
SELECT * FROM `users` WHERE ((`is_verified` = 1) AND (`first_name` like '%%' or `middle_name` like '%%' or `last_name` like '%%' or `email` like '%%'))
and i have this in my code我的代码中有这个
$user->where([
['is_verified', '=', 1]
])
->where('first_name', 'like', "%$search%")
->orWhere('middle_name', 'like', "%$search%")
->orWhere('last_name', 'like', "%$search%")
->orWhere('email', 'like', "%$search%");
but it produces但它产生
SELECT * FROM `users` WHERE ((`is_verified` = '1') and `first_name` like '%%' or `middle_name` like '%%' or `last_name` like '%%' or `email` like '%%')
You have to use an anonymous function in a "closure-where" clause.您必须在“closure-where”子句中使用匿名函数。
$user->where([
['is_verified', '=', 1]
])->where(function ($query) use ($search) {
$query->where('first_name', 'like', "%$search%")
->orWhere('middle_name', 'like', "%$search%")
->orWhere('last_name', 'like', "%$search%")
->orWhere('email', 'like', "%$search%");
});
you must use anonymous function like following code:您必须使用匿名函数,如以下代码:
User::where(function ($query){
$query->where('is_verified', 1);
})->where(function ($query) use ($search) {
$query->where('first_name', 'like', "%$search%")
->orWhere('middle_name', 'like', "%$search%")
->orWhere('middle_name', 'like', "%$search%")
->orWhere('email', 'like', "%$search%");
})->toSql();
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