用特定术语替换单元格

Question

I want to replace the words contains "conference" and "group" with "N/A" in the dataframe. Eg "AAAI Conference"->"N/A" "Alibaba Group" -> "N/A"

The dataframe is called name , I try two ways to do this:

columns=['nameCurrentEmployer',
       'name2ndEmployer', 'name3rdEmployer',
       'name4thEmployer', 'name5thEmployer',
       'name6thEmployer', 'name7thEmployer',
       'name8thEmployer', 'name9thEmployer',
       'name10thEmployer'] 
name.loc[name.str.contains(['conference','group'], case=False), columns] = 'N/A'

Prompt error AttributeError: 'DataFrame' object has no attribute 'str'

NAMES = pd.Series(name.values.flatten())
NAMES.loc[NAMES.str.contains(['conference','group'], case=False), columns] = 'N/A'

Now the error is

TypeError: unhashable type: 'list'

Thank you very much.

Answer 1

str.contains() takes

Character sequence or regular expression.

---

So instead of ['conference','group'] you should use 'conference|group' :

NAMES.loc[NAMES.str.contains('conference|group', case=False), columns] = 'N/A'

---

Alternatively, I would suggest to use either apply() :

NAMES.name = NAMES.name.apply(lambda x: 'N/A' if 'conference' in x else x)

or str.replace()