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WatchOS 上的 SwiftUI - 用于启动活动或锻炼应用程序的代码？

[英]SwiftUI on WatchOS - code for launching Activity or Workout App?

原文 2020-02-04 00:03:33 9 1 swiftui/ watchos/ launching-application

I have a SwiftUI app in which I would like to show the "WorkOut" and "Activity" icons and launch those apps when the respective icon is tapped.我有一个 SwiftUI 应用程序，我想在其中显示“锻炼”和“活动”图标，并在点击相应图标时启动这些应用程序。

Is this possible in WatchOS6 & SwiftUI?这在 WatchOS6 和 SwiftUI 中可能吗？

I know this "can I launch another app from within my app" question has been asked before for iOS or WatchOS but the answers seem old and I was hoping that this is now possible in WatchOS 6.我知道这个“我可以从我的应用程序中启动另一个应用程序吗”的问题之前曾被问到 iOS 或 WatchOS，但答案似乎很旧，我希望现在可以在 WatchOS 6 中实现。

Thanks!谢谢！

Gerard杰拉德

1 个解决方案

MKMapItem has a method openInMaps() that you can use to open the Maps app. MKMapItem有一个openInMaps()方法，您可以使用它来打开地图应用程序。

I don't think there is an equivalent for the Workout/Activity apps.我认为锻炼/活动应用程序没有等效项。

Also, I seems like using their icons is against the guidelines.另外，我似乎使用他们的图标违反了指导方针。 You can only use the rings.您只能使用戒指。

https://developer.apple.com/design/human-interface-guidelines/healthkit/overview/ https://developer.apple.com/design/human-interface-guidelines/healthkit/overview/

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