如何按字母顺序倒序排序列表但首先是数字

Question

I'm coding a simple blackjack program they way I coded I need "A" to be sorted to the end of the list so it must be reversed alphabetically and all the numbers should be checked before it

revelant part of the code:

oyuncukart = []
eroskart = []
oyuncuToplam = 0
erosToplam = 0

def Donustur(El,oyuncuTop):
    aTane = El.count("A")
    for kart in El:
        if "2" == kart:
            oyuncuTop += 2
        if "3" == kart:
            oyuncuTop += 3
        if "4" == kart:
            oyuncuTop += 4
        if "5" == kart:
            oyuncuTop += 5
        if "6" == kart:
            oyuncuTop += 6
        if "7" == kart:
            oyuncuTop += 7
        if "8" == kart:
            oyuncuTop += 8
        if "9" == kart:
            oyuncuTop += 9
        if "10" == kart:
            oyuncuTop += 10
        if "J" == kart:
            oyuncuTop += 10
        if "Q" == kart:
            oyuncuTop += 10
        if "K" == kart:
            oyuncuTop += 10
        if "A" == kart and aTane == 1 and oyuncuTop <= 10:
            oyuncuTop += 11
        elif "A" == kart and aTane == 1 and oyuncuTop > 10:
            oyuncuTop += 1
        elif "A" == kart and aTane > 1  and oyuncuTop < 10:
            oyuncuTop += 11
        elif "A" == kart and aTane > 1 and oyuncuTop >= 10:
            oyuncuTop += 1

    return oyuncuTop

kartlar = ["A","2","3","4","5","6","7","8","9","10","J","Q","K"]


oyuncukart.append(random.choice(kartlar))
oyuncukart.append(random.choice(kartlar))
oyuncukart.sort(reverse=True)

Answer 1

You don't want to sort numerically or alphabetically (reversed or not); you want the Very Special sort order 2,3,4,5,6,7,8,9,J,Q,K,A .

You can apply a custom order to sort inside the command itself:

oyuncukart.sort(key=["2","3","4","5","6","7","8","9","10","J","Q","K","A"].index)

and this might produce (with more draws than 2 -- but it's only about the sort order so that doesn't matter) a sequence such as this:

['2', '10', 'J', 'Q', 'A']

Answer 2

I would approach this in a different way, with a function that returns the value of the card that can be used as a key argument to sorted() . That would give us the following:

Code:

face_cards = {'J': 11,
              'Q': 12,
              'K': 13,
              'A': 14}

def card_val(card):
    try:
        return int(card)
    except ValueError:
        return face_cards[card]

kartlar = ["A","2","3","4","5","6","7","8","9","10","J","Q","K"]

sorted_kartlar = sorted(kartlar, key=card_val)

Usage:

>>> import random
>>> kartlar = ["A","2","3","4","5","6","7","8","9","10","J","Q","K"]
>>> random.shuffle(kartlar)
>>> kartlar
['6', '4', '10', 'J', '2', 'A', 'K', '8', '3', '5', 'Q', '9', '7']
>>> sorted(kartlar, key=card_val)
['2', '3', '4', '5', '6', '7', '8', '9', '10', 'J', 'Q', 'K', 'A']