你能通过多重赋值将 True 或 False 随机分配给一组变量吗？

Question

I would like to assign either True or False to the first variable and then have a second variable assignment be the opposite of the first one. If the first variable is assigned a value of False , then the second variable should become True , and vice versa. My first thought was to do this with an if/else-statement, but it became apparent that there were too many assignments:

Example 1:

import random

if random.choice([True, False]):
  player_turn = True
  computer_turn = False
else:
  player_turn = False
  computer_turn = True


print(player_turn)
print(computer_turn)

I then decided to simplify the logic by leveraging the information from the first variable assignment:

Example 2:

import random

player_turn = random.choice([True, False])
computer_turn = not player_turn

print(player_turn)
print(computer_turn)

Is it possible to reduce this down even further? Perhaps, by utilizing multiple assignment to have this be just one line of code?

Answer 1

Use random.sample instead of random.choice . Since it picks values without replacement, the second element is necessarily whichever value wasn't chosen first.

player_turn, computer_turn = random.sample([True, False], 2)

Or, use an assignment expression (Python 3.8 or later) so that you can negate whichever value is return by random.choice :

player_turn, computer_turn = (c := random.choice([True, False]), not c)

In practice, though, don't maintain two variables whose values have to be kept in sync. One variable indicating whose turn it is suffices.

Answer 2

If you really must:

x, y = [i[1] if i[0]==0 else not i[1] for i in enumerate([random.choice([True, False])]*2)]

I guess you get the idea that the two lines are actually not that bad.