无法在 HTML onclick 中的参数中传递 php 变量

Question

I am trying to pass more then 1 php variable in parameter in a onclick.

<button type="button" class="btn btn-dark bmd-btn-fab bmd-btn-fab-sm" 
onclick="<?php echo 'analyse(\'' . $name . '\', \''. $type .'\')'; ?>">
    <img src="../assets/add.png" />
</button>

For only 1 parameter it worked with this :

onclick=<?php echo "analyse('$name')"; ?>"

and this:

onclick="<?php echo 'analyse(\'' . $name . '\')'; ?>"

Answer 1

I would put this as a comment but the placeholder text in comments says to not put answers in comments...

First, analyse has to be a JS function, not a PHP function.. Also, you don't need to put analyse inside of the <?php code block..

<button onclick="analyse('<?php echo $name ?>', '<?php echo $type ?>')">

Full demo PHP file:

<?php
$name = "John Smith";
$type = "Best Type"
?>
<div>
    <button onclick="analyze('<?php echo $name ?>', '<?php echo $type ?>')">Show Name</button>
    <p id="results"></p>
</div>
<script>
    function analyze(name, type) {
        document.getElementById("results").innerHTML = "<b>NAME:</b> " + name + " <b>TYPE:</b> " + type;
    }
</script>

To elaborate, just in case you wanted to use a PHP function to return a name or type, you would use it like so:

<?php
$name = "John Smith";
$type = "Best Type";

function get_Name($nameToGet) {
    return $nameToGet;
}

function get_Type($typeToGet) {
    return $typeToGet;
}
?>
<div>
    <button onclick="analyze('<?php echo get_Name($name) ?>', '<?php echo get_Type($type) ?>')">Show Name</button>
    <p id="results"></p>
</div>
<script>
    function analyze(name, type) {
        document.getElementById("results").innerHTML = "<b>NAME:</b> " + name + " <b>TYPE:</b> " + type;
    }
</script>