在bash中运行while循环时二元运算符预期错误

Question

TL:DR

Check if a given PID is running, if yes kill the process.

count=0
  while [[ "$count" -le 3 && ps -p $pid > /dev/null ]];
  do
   kill -9 $pid
   count=$(( $count + 1 )):
  done

To this I am getting an error as:

line 8: [: -p: binary operator expected

I am aware there are several similar questions, I already tried their solutions but it doesn't seem to work.

Answer 1

The while loop is logically incorrect, as @kvantour mentioned. Here is the script. Note that it will let you know if it could not kill the process, so you can investigate the root cause. The script gets PID as its first argument (eg $./kill-pid.sh 1234 ) Note that this works for bash ver. 4.1+:

#!/usr/bin/env bash

if ps -p $1 > /dev/null

then
  output=$(kill -9 $1 2>&1)
    if [ $? -ne 0 ]
    then
      echo "Process $1 cannot be killed. Reason:"
      echo "$output"
# This line is added per OP request, to try to re-run the kill command if it failed for the first time.
#      kill -9 $1
    fi
fi