在最大列值上获取不同的行

Question

I need a row of the table on the max column value

SELECT  MAX(PromoFileVersion) AS PromoFileVersion
        , FYearWeek
        , WeekPriority
        , PromoEventId  
FROM PromoCalendar   
GROUP BY FYearWeek, WeekPriority, PromoEventId

But I am getting duplicate records

Any help?

Answer 1

SELECT PromoFileVersion, FYearWeek, WeekPriority, PromoEventId  
FROM PromoCalendar p
where PromoFileVersion = (select max(PromoFileVersion) PromoFileVersion
                          from PromoCalendar p1
                          where p1.FYearWeek = p.FYearWeek 
                          and p1.WeekPriority = p.WeekPriority
                          GROUP BY  FYearWeek, WeekPriority);

Here is a DEMO

Answer 2

You can use row_number() :

select pc.*
from (select pc.*, 
             row_number() over (partition by FYearWeek, WeekPriority order by PromoFileVersion desc) as seq
      from PromoCalendar  pc
     ) pc
where pc.seq = 1;

If you have ties with PromoFileVersion then you cas use dense_rank() instead.