Git：如何获取所有未跟踪文件的列表，忽略未跟踪的子模块？

Question

In a script, I want to check whether a Git repository is clean or not. In case it's not clean, changes should be stashed away. For the check, I'm using:

git diff-index HEAD --

to figure out modifications of tracked files and:

git ls-files --others

to figure out whether untracked files are present. Unfortunately, git ls-files --others will also report untracked submodules which can't be stashed away.

Is there some option or a different Git command which returns the same result as git ls-files --other except of untracked submodules ?

Answer 1

git cannot see whether an untracked directory is supposed to become a submodule or not. It is just an untracked directory.

You might check for a .git subdirectory to check if that untracked directory is in fact a git repository; something like:

for untracked in $(git ls-files --others)
do
    if [ ! -e $untracked/.git ]
    then
        echo $untracked
    fi
done

which would print the untracked files/directories that are not a git repository.

Git alias

you can set it up as a git alias like this:

git config --global alias.untracked-not-repo '!'"bash -c 'for untracked in \$(git ls-files --others); do if [ ! -e \$untracked/.git ]; then echo \$untracked; fi; done'"

now you can use it like

git untracked-not-repo