如何使用正则表达式从python中的字符串打印印地语字符？

Question

I'm using regex in python and trying to extract 'Hindi' character from the given string and then print it but I'm not able to do so. I'm trying to extract जनवरी12 and जनवरी22 from the string. The code should search for a phrase that starts with जनवरी(or any hindi character) and ends with 12( or any number). Here is the code:

import re

string = "विश्व कप sdsd 12वें संस्करण जनवरी12 or 12जनवरी or जनवरी22"
mo = re.compile(r'[^(^a-zA-Z-0-9)]+\d+')
print(mo.findall(string))

Output: [' 12', 'वें संस्करण जनवरी12', ' 12', ' जनवरी22']

I know that [^abc] matches any character that isn't between the brackets and tried to achieve the same with [^(^a-zA-Z-0-9)]+ but the output is not what I expected.

Expected output: जनवरी12, जनवरी22

Can anyone explain me how this should be done and matching the start and end in Python's regex?

Answer 1

I think you just need a pattern that matches 1+ letters (with 0 or more diacritics after each) and then 1+ digits.

See a Python demo that outputs ['जनवरी12', 'जनवरी22'] :

import re
s = "विश्व कप sdsd 12वें संस्करण जनवरी12 or 12जनवरी or जनवरी22"
combining_marks = '[\u0300-\u036F\u0483-\u0489\u0591-\u05BD\u05BF\u05C1\u05C2\u05C4\u05C5\u05C7\u0610-\u061A\u064B-\u065F\u0670\u06D6-\u06DC\u06DF-\u06E4\u06E7\u06E8\u06EA-\u06ED\u0711\u0730-\u074A\u07A6-\u07B0\u07EB-\u07F3\u07FD\u0816-\u0819\u081B-\u0823\u0825-\u0827\u0829-\u082D\u0859-\u085B\u08D3-\u08E1\u08E3-\u0903\u093A-\u093C\u093E-\u094F\u0951-\u0957\u0962\u0963\u0981-\u0983\u09BC\u09BE-\u09C4\u09C7\u09C8\u09CB-\u09CD\u09D7\u09E2\u09E3\u09FE\u0A01-\u0A03\u0A3C\u0A3E-\u0A42\u0A47\u0A48\u0A4B-\u0A4D\u0A51\u0A70\u0A71\u0A75\u0A81-\u0A83\u0ABC\u0ABE-\u0AC5\u0AC7-\u0AC9\u0ACB-\u0ACD\u0AE2\u0AE3\u0AFA-\u0AFF\u0B01-\u0B03\u0B3C\u0B3E-\u0B44\u0B47\u0B48\u0B4B-\u0B4D\u0B56\u0B57\u0B62\u0B63\u0B82\u0BBE-\u0BC2\u0BC6-\u0BC8\u0BCA-\u0BCD\u0BD7\u0C00-\u0C04\u0C3E-\u0C44\u0C46-\u0C48\u0C4A-\u0C4D\u0C55\u0C56\u0C62\u0C63\u0C81-\u0C83\u0CBC\u0CBE-\u0CC4\u0CC6-\u0CC8\u0CCA-\u0CCD\u0CD5\u0CD6\u0CE2\u0CE3\u0D00-\u0D03\u0D3B\u0D3C\u0D3E-\u0D44\u0D46-\u0D48\u0D4A-\u0D4D\u0D57\u0D62\u0D63\u0D82\u0D83\u0DCA\u0DCF-\u0DD4\u0DD6\u0DD8-\u0DDF\u0DF2\u0DF3\u0E31\u0E34-\u0E3A\u0E47-\u0E4E\u0EB1\u0EB4-\u0EBC\u0EC8-\u0ECD\u0F18\u0F19\u0F35\u0F37\u0F39\u0F3E\u0F3F\u0F71-\u0F84\u0F86\u0F87\u0F8D-\u0F97\u0F99-\u0FBC\u0FC6\u102B-\u103E\u1056-\u1059\u105E-\u1060\u1062-\u1064\u1067-\u106D\u1071-\u1074\u1082-\u108D\u108F\u109A-\u109D\u135D-\u135F\u1712-\u1714\u1732-\u1734\u1752\u1753\u1772\u1773\u17B4-\u17D3\u17DD\u180B-\u180D\u1885\u1886\u18A9\u1920-\u192B\u1930-\u193B\u1A17-\u1A1B\u1A55-\u1A5E\u1A60-\u1A7C\u1A7F\u1AB0-\u1ABE\u1B00-\u1B04\u1B34-\u1B44\u1B6B-\u1B73\u1B80-\u1B82\u1BA1-\u1BAD\u1BE6-\u1BF3\u1C24-\u1C37\u1CD0-\u1CD2\u1CD4-\u1CE8\u1CED\u1CF4\u1CF7-\u1CF9\u1DC0-\u1DF9\u1DFB-\u1DFF\u20D0-\u20F0\u2CEF-\u2CF1\u2D7F\u2DE0-\u2DFF\u302A-\u302F\u3099\u309A\uA66F-\uA672\uA674-\uA67D\uA69E\uA69F\uA6F0\uA6F1\uA802\uA806\uA80B\uA823-\uA827\uA880\uA881\uA8B4-\uA8C5\uA8E0-\uA8F1\uA8FF\uA926-\uA92D\uA947-\uA953\uA980-\uA983\uA9B3-\uA9C0\uA9E5\uAA29-\uAA36\uAA43\uAA4C\uAA4D\uAA7B-\uAA7D\uAAB0\uAAB2-\uAAB4\uAAB7\uAAB8\uAABE\uAABF\uAAC1\uAAEB-\uAAEF\uAAF5\uAAF6\uABE3-\uABEA\uABEC\uABED\uFB1E\uFE00-\uFE0F\uFE20-\uFE2F\U000101FD\U000102E0\U00010376-\U0001037A\U00010A01-\U00010A03\U00010A05\U00010A06\U00010A0C-\U00010A0F\U00010A38-\U00010A3A\U00010A3F\U00010AE5\U00010AE6\U00010D24-\U00010D27\U00010F46-\U00010F50\U00011000-\U00011002\U00011038-\U00011046\U0001107F-\U00011082\U000110B0-\U000110BA\U00011100-\U00011102\U00011127-\U00011134\U00011145\U00011146\U00011173\U00011180-\U00011182\U000111B3-\U000111C0\U000111C9-\U000111CC\U0001122C-\U00011237\U0001123E\U000112DF-\U000112EA\U00011300-\U00011303\U0001133B\U0001133C\U0001133E-\U00011344\U00011347\U00011348\U0001134B-\U0001134D\U00011357\U00011362\U00011363\U00011366-\U0001136C\U00011370-\U00011374\U00011435-\U00011446\U0001145E\U000114B0-\U000114C3\U000115AF-\U000115B5\U000115B8-\U000115C0\U000115DC\U000115DD\U00011630-\U00011640\U000116AB-\U000116B7\U0001171D-\U0001172B\U0001182C-\U0001183A\U000119D1-\U000119D7\U000119DA-\U000119E0\U000119E4\U00011A01-\U00011A0A\U00011A33-\U00011A39\U00011A3B-\U00011A3E\U00011A47\U00011A51-\U00011A5B\U00011A8A-\U00011A99\U00011C2F-\U00011C36\U00011C38-\U00011C3F\U00011C92-\U00011CA7\U00011CA9-\U00011CB6\U00011D31-\U00011D36\U00011D3A\U00011D3C\U00011D3D\U00011D3F-\U00011D45\U00011D47\U00011D8A-\U00011D8E\U00011D90\U00011D91\U00011D93-\U00011D97\U00011EF3-\U00011EF6\U00016AF0-\U00016AF4\U00016B30-\U00016B36\U00016F4F\U00016F51-\U00016F87\U00016F8F-\U00016F92\U0001BC9D\U0001BC9E\U0001D165-\U0001D169\U0001D16D-\U0001D172\U0001D17B-\U0001D182\U0001D185-\U0001D18B\U0001D1AA-\U0001D1AD\U0001D242-\U0001D244\U0001DA00-\U0001DA36\U0001DA3B-\U0001DA6C\U0001DA75\U0001DA84\U0001DA9B-\U0001DA9F\U0001DAA1-\U0001DAAF\U0001E000-\U0001E006\U0001E008-\U0001E018\U0001E01B-\U0001E021\U0001E023\U0001E024\U0001E026-\U0001E02A\U0001E130-\U0001E136\U0001E2EC-\U0001E2EF\U0001E8D0-\U0001E8D6\U0001E944-\U0001E94A\U000E0100-\U000E01EF]'
mo = re.compile(r'(?:[^\W\d_]{}*)+\d+'.format(combining_marks))
print(mo.findall(s))

Note that r'(?:[^\\W\\d_]{}*)+\\d+'.format(combining_marks) creates a pattern that matches

• (?:[^\\W\\d_]{}*)+ - one or more occurrences of
  • [^\\W\\d_] - any Unicode base letter (if you want to disallow ASCII letters, add (?![A-Za-z]) right before this pattern)
  • {}* - zero or more occurrences of combining_marks
• \\d+ - 1+ digits

So, if you want to avoid matching ASCII letters, in the above code, use

r'(?:(?![A-Za-z])[^\W\d_]{}*)+\d+'