如何合并列表中具有相等值的字典并连接不相等的值并将其他字段保留在字典中？

Question

there is list of dictionaries, when id in two or more dict are equal,names are equal too,but codes are different.

[
    {
        "id" : 2.0,
        "name":"x",
        "code" : "12345"
    },
    {
        "id" : 2.0,
        "name":"x",
        "code" : "23456"
    },
    {
        "id" : 4.0,
        "name":"y",
        "code" : "6767"
    },
    {
        "id" : 5.0,
        "name":"z",
        "code" : "567"
    },
    {
        "id" : 4.0,
        "name":"y",
        "code" : "55657"
    }
]

I want to merge dict that have common id, then i want to have this list as you can see:

[
    {
        "id" : 2.0,
        "name":"x",
        "code" : "12345,23456"
    },
    {
        "id" : 4.0,
        "name":"y",
        "code" : "6767,55657"
    },
    {
        "id" : 5.0,
        "name":"z",
        "code" : "567"
    }
]

Answer 1

You can do this using the library pandas .

import pandas as pd
# Here, L1 is your former list
L2 = pd.DataFrame(L1).groupby(["id", "name"], as_index=False).agg({"code": lambda x: ','.join(x.tolist())}).to_json(orient="records")
print(L2)

Output

[
  {
    "id": 2.0,
    "name": "x",
    "code": "12345,23456"
  },
  {
    "id": 4.0,
    "name": "y",
    "code": "6767,55657"
  },
  {
    "id": 5.0,
    "name": "z",
    "code": "567"
  }
]

EDIT: Fixed List to String

Answer 2

You should loop through the dictionary like this:

dictionary_aux = []
for elem in dictionary:
    found = False
    for new_elem in dictionary_aux:
        if new_elem.id == elem.id:
             new_elem.code = new_elem.code + "," elem.code
             found = True
             break
    if not found:
         dictionary_aux.append(elem)

You have the result in dictionary_aux. I hope it helps.