用户写“exit”时如何退出程序？

Question

i'm writing a program asking the user to guess number which already generated automatically. the think that as per below code the user should to enter int number but what if the user enter "exit" to exit the program it will show an error due "exit" is string not int, how to solve this issue since i tried to find the solution but i did not find the proper answer

import random
import sys

def GuessedNumber():

    while(True):
        Generate = random.randint(1,9)

        GuessNumber = int(input("Dear user kidnly guess a number between 1-9: "))

        if GuessNumber == Generate:
            print("You guessed right number")

        elif GuessNumber > Generate:
            print("Guessed number is too high")

        elif GuessNumber < Generate:
            print("Guessed number is too low")



GuessedNumber()

Answer 1

将输入分配给一个字符串，然后检查exit ，只有当它不匹配时才继续转换为整数变量。

Answer 2

You can check the input is in valid range 1-9 or not. If the input is in the range then do what you were doing, else if the input is exit then exit the game otherwise say him to enter valid input and continue the loop. Here is the code:

import random

def GuessedNumber():
    while(True):
        Generate = random.randint(1,9)
        GuessNumber = input("Dear user kidnly guess a number between 1-9: ")
        if GuessNumber in list('123456789'):
            GuessNumber = int(GuessNumber)
            if GuessNumber == Generate:
                print("You guessed right number")
            elif GuessNumber > Generate:
                print("Guessed number is too high")
            elif GuessNumber < Generate:
                print("Guessed number is too low")
        else:
            if GuessNumber == 'exit':
                print('Good bye!')
                break
            else: # for any other non invalid input
                print('Please enter a valid input')
                continue

GuessedNumber()