比较两个对象数组以获得不同的结果

Question

 accounts: [ 
  { 
    uuid: '47833371-753a-412a-a00c-b43fc48b662b',
    cash: 50000 
  }, { 
    uuid: 'b9a30e79-7dc6-45c7-b277-6f03b43f0f9a',
    cash: 40000 
  } 
],
participations: [ 
  { 
    product_id: '0ebe9585-9506-4e28-8ca1-561726d51e30',
    number_participations: 283,
    net_asset_value: '4.0000000000',
    id_account: '47833371-753a-412a-a00c-b43fc48b662b' 
  },{ 
    product_id: '658d56f9-37f6-44ea-b528-861068be4743',
    number_participations: 100,
    net_asset_value: '8.0000000000',
    id_account: '47833371-753a-412a-a00c-b43fc48b662b' 
  } 
] 
}

I have two arrays of objects, I want to go through both at the same time, and obtain the patrimony of each of them separately, and then, when listing all accounts, each one has its patrimony added to its object.

let patrimony = 0
for (let i = 0; i < participations.length; i++) {
    for (let j = 0; j < accounts.length; j++) {
        if (participations[i].uuid_account === accounts[j].uuid) {
            patrimony += participations[i].participations * parseFloat(participations[i].net_asset_value);
        }
    }
}

With my approach, what I am getting is simply the sum of the participations multiply for the asset value of the participation of both accounts.

"accounts": [
  {
    "uuid": "47833371-753a-412a-a00c-b43fc48b662b",
    "patrimony": 1932,

  },
  {
    "uuid": "b9a30e79-7dc6-45c7-b277-6f03b43f0f9a",
    "patrimony": 1932,
  }
]

What I want and I don't know how it's to get the patrimony of each account and add it to correspondent object. Thanks in advance.

Answer 1

I think there is a few errors. Please check the fix here.

 let patrimony = 0 for (let i = 0; i < participations.length; i++) { for (let j = 0; j < accounts.length; j++) { // error if (participations[i].uuid_account === accounts[j].uuid) { if (participations[i].id_account === accounts[j].uuid) { // error patrimony += participations[i].participations * parseFloat(participations[i].net_asset_value); patrimony += participations[i].number_participations * parseFloat(participations[i].net_asset_value); } } }

Answer 2

The description of the problem doesn't exactly match the provided code, but I guess you could use a combination of map / filter / reduce to get your results. This is how I would do it, assuming accounts and participants are object keys of a data object:

data.accounts = data.accounts.map(function (account) {
  account.patrimony = data.participations
    .filter(function (participation) {
      return participation.id_account === account.uuid;
    })
    .reduce(function (accumulator, currentValue) {
      return accumulator + (currentValue.number_participations * parseFloat(currentValue.net_asset_value));
    }, 0);

  return account;
});

Here's a link showing the full working code:

https://jsfiddle.net/fv7hb8oL/