读取多个 CSV，每列都有其 CSV 名称

Question

to sum up i need that each colum as the name that the csv file has.

This is what I have done so far :

path = r'C:\Users\dfgdfsgsfg\Untitled Folder\tickers' # use your path
all_files = glob.glob(os.path.join(path, "*.csv"))     # advisable to use os.path.join as this makes concatenation OS independent

df_from_each_file = (pd.read_csv(f , parse_dates=True, index_col="date") for f in all_files)

concat = pd.concat(df_from_each_file, axis=1)

df = concat['PriceUSD']

df.columns = [ ??????? ] #what do I put in here?

This what I get when I dont name the columns

Answer 1

i also tryied this , but not quiet the results i wished

all_files = glob.glob(os.path.join(path, "*.csv"))     # advisable to use os.path.join as this makes concatenation OS independent

df_from_each_file = (pd.read_csv(f , parse_dates=True, index_col="date").assign(filename = f) for f in all_files)

concat = pd.concat(df_from_each_file, axis=1)

df = concat['PriceUSD']

df.columns = all_files[:-2]

df

RESULT

Answer 2

If you are really interested in only the single column from all those CSV files, then while parsing the csv just trim it to just the column you want:

def getPriceUSD(filename):
    """reads csv file then returns dataframe with just the column 'PriceUSD'
    with the filename as the column title"""
    data = pd.read_csv(f , parse_dates=True, index_col="date")
    data = data["PriceUSD"]
    data.columns = [filename]
    return data

Then concat all the already parsed and formatted columns together:

df = pd.concat(map(getPriceUSD, all_files), axis=1)

And before you ask, if you don't want the full path then use os.path.basename(filename) for the column instead of just filename