[英]How can I get text inside of <span> using puppeteer?
Having the following html:具有以下 html:
<div class="col-xs-6 col-md-6 nopaddingright">
<ul class="account-statics clearright">
<li>
<span class="title">Title1</span>
<span class="value fs13 ">value1</span>
</li>
<li>
<span class="title">Title2</span>
<span class="value fs13 ">value2</span>
<ul class="account-sub">
<li>
<span class="title">Title3</span>
<span class="value fs13 ">value3</span>
</li>
<li>
<span class="title">Title4</span>
<span class="value fs13 ">value4</span>
</li>
</ul>
</li>
<li>
<span class="title">Title5</span>
<span class="value fs13 ">value5</span>
</li>
</ul>
</div>
I wanna get the text inside of all second elements.我想在所有第二个元素中获取文本。
I tried this way:我试过这样:
const element = await page.$('div > ul[class="account-statics clearright"] > ul > li:nth-child(2) > span:nth-child(2)');
And another way:另一种方式:
const elements= await page.$$('span[class="value fs13 "]');
But both attempts didn't work.但两次尝试都没有奏效。 How can I solve this?我该如何解决这个问题?
const sp = await page.$x('//*[contains(@class, "fs13")]');
const spanName = await (await sp.getProperty('textContent')).jsonValue();
The following code will get you the span text assuming the class name in span is fs13.假设 span 中的类名称为 fs13,以下代码将为您提供 span 文本。
There shouldnot be '.'不应该有'.' infront of fs13 in $x function. $x 函数中 fs13 的前面。 It should be only fs13 as we have already mentioned it is class它应该只是 fs13,因为我们已经提到它是类
sp.getProperty is not a function sp.getProperty 不是 function
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