根据 select 值筛选表行数

Question

For example: Choose 4 -> display 4 rows, choose 6 -> display 6 rows

• Link: https://codepen.io/quyen_nguyen/pen/YzXyBrQ

Answer 1

option value will be number not string

<option value="4">4</option> not

<option value="a1">4</option>

 $('.filter-handle').on('change', function(e) { var $rows = $('#table').find('tr'); var showRow = Number(e.target.value)+1; $rows.hide().slice(0, showRow).show(); });

 <script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script> <select class="filter-handle"> <option value="4">4</option> <option value="6">6</option> <option value="8">8</option> </select> <table class="filter-table-data" id="table"> <tr><th scope="col">Name</th><th scope="col">Des</th></tr> <tr><td>Vu Tran</td><td>Sunnyvale</a></tr> <tr><td>Michelle Case</td><td>Sunnyvale</a></tr> <tr><td>Todd Linden</td><td>Madison</a></tr> <tr><td>Michael Liston</td><td>Madison</a></tr> <tr><td>Vu Tran</td><td>Sunnyvale</a></tr> <tr><td>Michelle Case</td><td>Sunnyvale</a></tr> <tr><td>Todd Linden</td><td>Madison</a></tr> <tr><td>Michael Liston</td><td>Madison</a></tr> <tr><td>Vu Tran</td><td>Sunnyvale</a></tr> <tr><td>Michelle Case</td><td>Sunnyvale</a></tr> <tr><td>Todd Linden</td><td>Madison</a></tr> <tr><td>Michael Liston</td><td>Madison</a></tr> </table>