[英]Ansible how use with_dict by extra_vars?
how can I use with_dict by extra_vars?如何通过 extra_vars 使用 with_dict?
I try I know everything but all output with_dict expects a dict :(我试着我知道一切,但所有输出 with_dict 都需要一个 dict :(
This is all files这是所有文件
# vars.yml
rd1:
Terry:
user_name:terry_liu
user_birth:1994/05/11
Cary:
user_name:cary_lin
user_birth:1992/02/19
rd6:
Jessie:
user_name:jessie_chen
user_birth:1996/11/20
Sherry:
user_name:sherry_hsu
user_birth:1989/07/23
- ——
# test.yml
- name: demo
hosts: test
vars_files:
- vars.yml
tasks:
- name: show data
debug:
msg: "{{ item }}"
with_dict: "{{ dep }}"
- ——
#command
ansible-playbook -i inventory test.yml --extra-vars 'dep=rd1'
- ——
Inventory's host is my test vm, just have an ip and it can be ssh. Inventory 的主机是我的测试虚拟机,只要有一个 ip 就可以是 ssh。
When run command, it output: fatal: [172.16.1.227]: FAILED!运行命令时,输出: fatal: [172.16.1.227]: FAILED! => {"msg": "with_dict expects a dict"}
=> {"msg": "with_dict 需要一个 dict"}
I think it's need var in var, but I try many different way, all fail.我认为它需要 var in var,但我尝试了很多不同的方法,都失败了。
My demand is send a float dep var and get correspond data from vars.yml.我的需求是发送一个 float dep var 并从 vars.yml 获取相应的数据。
Thanks all, have a good day!谢谢大家,祝你有美好的一天!
The problem is that "{{ dep }}"
evaluates to the string "rd1"
问题是
"{{ dep }}"
计算结果为字符串"rd1"
with_dict: "{{ dep }}"
This is the reason for the error "with_dict expects a dict"
.这就是错误
"with_dict expects a dict"
。
Instead, you need lookup
and vars
plugin.相反,您需要
lookup
和vars
插件。 For example例如
with_dict: "{{ lookup('vars', dep) }}"
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