[英]Regex Match containing string between 2 characters
I'm trying to match a string in an HTTP page between ><
.我正在尝试匹配 HTTP 页面中><
之间的字符串。
I'm having trouble with the first >
as it also matches subsequent chars.我在使用第一个>
遇到问题,因为它也匹配后续字符。 eg.例如。 in this example在这个例子中
<a href="https://stackoverflow.com" class="-logo js-gps-track"
data-gps-track="top_nav.click({is_current:false, location:3, destination:8})">
<span class="-img _glyph">Stack Overflow</span>
</a>
I would only want to match Stack Overflow
.我只想匹配Stack Overflow
。 I've currently got \\>([^\\>].*Stack Overflow.*)\\<
but that matches everything after the first >
ie我目前有\\>([^\\>].*Stack Overflow.*)\\<
但这与第一个之后的所有内容匹配>
即
><span class="-img _glyph">Stack Overflow<
Any help would be great任何帮助都会很棒
It'd probably be more elegant to use DOMParser, and take the textContent
of .-img._glyph
:使用 DOMParser 并采用.-img._glyph
的textContent
可能会更优雅:
const str = `<a href="https://stackoverflow.com" class="-logo js-gps-track" data-gps-track="top_nav.click({is_current:false, location:3, destination:8})"> <span class="-img _glyph">Stack Overflow</span> </a>`; console.log( new DOMParser().parseFromString(str, 'text/html').querySelector('.-img._glyph').textContent );
If you had to use regex, instead of repeating .
如果您必须使用正则表达式,而不是重复.
(which matches anything), repeat [^<>]
(which matches anything which isn't a <
or >
) on either side of the Stack Overflow
part, while looking ahead and behind for <
and >
: (匹配任何内容),在Stack Overflow
部分的任一侧重复[^<>]
(匹配任何不是<
或>
),同时向前和向后查看<
和>
:
(?<=>)[^<>]*Stack Overflow[^<>]*(?=<)
(If you can't use lookbehind, match the initial >
and capture everything afterwards, then extract the capture group) (如果不能使用lookbehind,匹配首字母>
,然后捕获所有内容,然后提取捕获组)
Try using lookbehind and lookahead assertions , as in this regex: (?<=>)Stack Overflow(?=<)
尝试使用lookbehind 和lookahead assertions ,就像在这个正则表达式中一样: (?<=>)Stack Overflow(?=<)
const text = `<a href="https://stackoverflow.com" class="-logo js-gps-track" data-gps-track="top_nav.click({is_current:false, location:3, destination:8})"> <span class="-img _glyph">Stack Overflow</span> </a>`; const regex = /(?<=>)Stack Overflow(?=<)/g; const found = text.match(regex); console.log(found);
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.