如何在没有输入元素或隐藏 UI 元素的情况下在 Angular 表单中分配值？

Question

I am working on this template-driven form, where I have a dropdown.

The dropdown has an ID as value and Name as the display value.

When I submit the form, I need both the values ID and Name to be in the form output

   <mat-form-field>
            <mat-label>State</mat-label>
            <mat-select [(ngModel)]="data.stateCode" name="StateCode" #yddfyty>
              <mat-option *ngFor="let state of stateOptions" [value]="state.ID">
                {{state.name}}
              </mat-option>
            </mat-select>
   </mat-form-field>

After submitting the form, I get a JSON

{
  StateCode: "Option I select in the Dropdown"
}

When I submit the form, I also want the StateName to be in the form output.

How do I assign the StateName selected in the Dropdown, to a model property in the template-driven form?

I can think of a way where we can use an element and hide the element, Is there any other way?

Is the only way to do it in the Typescript file after submitting?

Answer 1

ViewChild comes handy in these situations:

HTML File:

<mat-form-field>
            <mat-label>State</mat-label>
            <mat-select  name="StateCode" #ElementRef>
              <mat-option *ngFor="let state of stateOptions" [value]="state.ID">
                {{state.name}}
              </mat-option>
            </mat-select>
   </mat-form-field>

Component TS File:

first declare an viewchild variable:

@ViewChild('ElementRef') stateElement: any;

and later on you can use this variable when you submit the form:

    OnSubmit(){
     let selectedStateCode = this.stateElement.nativeElement.value//selected dropdown value
     let selectedStateText = this.stateElement.nativeElement.textContent //selected dropdown text
     //rest of your submit code;
    }

Answer 2

是的，根据给定的限制，您必须处理.ts文件中的表单提交。