[英]MS Access SQL Query for time In/Out attendance
I'm doing a project which involves time and attendance management.我正在做一个涉及时间和出勤管理的项目。 When I download data from the biometric reader, I got the records in the following format,
当我从生物识别阅读器下载数据时,我得到了以下格式的记录,
Attendance Log Table Name: dbo_CHECKINOUT
The user Table name is: dbo_USERINFO
考勤日志表名:
dbo_CHECKINOUT
用户表名: dbo_USERINFO
SELECT t.userid, dbo_USERINFO.NAME, DateValue(t.checktime) AS [date],
Max(IIf(t.counter=0,t.checktime,Null)) AS Log_In,
Max(IIf(t.counter=1,t.checktime)) AS LB_Out,
Max(IIf(t.counter=2,t.checktime,Null)) AS LB_In,
Max(IIf(t.counter=3,t.checktime)) AS Log_Out,
Format((Log_In-LB_Out)+(LB_In-Log_Out),"hh:nn:ss") AS WorkTime,
Format(LB_In-LB_Out,"hh:nn:ss") AS LunchBreak
FROM (
SELECT t.*,
(select count(*) from dbo_CHECKINOUT where userid = t.userid and datevalue(checktime) = datevalue(t.checktime) and checktime < t.checktime) AS [counter] FROM dbo_CHECKINOUT AS t) AS t INNER JOIN dbo_USERINFO ON t.USERID=dbo_USERINFO.USERID
GROUP BY t.userid, dbo_USERINFO.NAME, DateValue(t.checktime);
I want to show the above records as follows, (the Log_In, LB_Out, LB_In, Log_Out, WorkTime and LunchBreak are based on 'time') Someone from StackOverFlow helped me out to make this query我想将上述记录显示如下,(Log_In、LB_Out、LB_In、Log_Out、WorkTime 和 LunchBreak 基于“时间”) StackOverFlow 的某人帮我完成了这个查询
userid date Log_In LB_Out LB_In Log_Out WorkTime LunchBreak
1 16-Feb-20 11:10:10 AM 7:51:57 PM
1 17-Feb-20 11:28:17 AM
2 16-Feb-20 9:57:48 AM 1:58:19 PM 2:33:39 PM 9:29:29 PM 10:56:21 00:35:20
3 16-Feb-20 10:07:31 AM 1:45:15 PM 2:17:46 PM 9:29:20 PM 10:49:18 00:32:31
3 17-Feb-20 10:15:13 AM
4 16-Feb-20 10:36:01 AM 9:29:46 PM
4 17-Feb-20 10:28:54 AM
5 16-Feb-20 9:33:08 AM 1:57:46 PM 2:48:26 PM 9:29:25 PM 11:05:37 00:50:40
5 17-Feb-20 9:31:47 AM
Results:结果:
userid date Log_In LB_Out LB_In Log_Out WorkTime LunchBreak 1 16-Feb-20 11:10:10 AM 7:51:57 PM 1 17-Feb-20 11:28:17 AM 2 16-Feb-20 9:57:48 AM 1:58:19 PM 2:33:39 PM 9:29:29 PM 10:56:21 00:35:20 3 16-Feb-20 10:07:31 AM 1:45:15 PM 2:17:46 PM 9:29:20 PM 10:49:18 00:32:31 3 17-Feb-20 10:15:13 AM 4 16-Feb-20 10:36:01 AM 9:29:46 PM 4 17-Feb-20 10:28:54 AM 5 16-Feb-20 9:33:08 AM 1:57:46 PM 2:48:26 PM 9:29:25 PM 11:05:37 00:50:40 5 17-Feb-20 9:31:47 AM
Now the problem is, as you can see Userid:1 & Userid: 4 doesn't have a LunchBreak.现在的问题是,正如您所看到的 Userid:1 & Userid: 4 没有 LunchBreak。 So their 1st log would be Log_In & 2nd Log would be as a Log_Out & total work time would be between 1st(Log_In) & 2nd(Log_Out).
所以他们的第一个日志将是 Log_In & 2nd Log 将作为一个 Log_Out & 总工作时间将在 1st(Log_In) 和 2nd(Log_Out) 之间。
Please help to make this possible for me.请帮助我使这成为可能。
This fancy query will return the lunch breaks:这个奇特的查询将返回午休时间:
SELECT
dbo_UserInfo.UserId,
DateValue([CheckTime]) AS [Date],
TimeValue(Min([CheckTime])) AS LogIn,
(Select Max(TimeValue(T.CheckTime))
From dbo_UserInfo As T
Where T.UserId = dbo_UserInfo.UserId
And DateValue(T.CheckTime) = DateValue(dbo_UserInfo.CheckTime)
And T.CheckTime >
(Select Min(S.CheckTime)
From dbo_UserInfo As S
Where S.UserId = dbo_UserInfo.UserId
And DateValue(S.CheckTime) = DateValue(dbo_UserInfo.CheckTime))) As LogOut,
(Select Min(TimeValue(T.CheckTime))
From dbo_UserInfo As T
Where T.UserId = dbo_UserInfo.UserId
And DateValue(T.CheckTime) = DateValue(dbo_UserInfo.CheckTime)
And T.CheckTime >
(Select Min(S.CheckTime)
From dbo_UserInfo As S
Where S.UserId = dbo_UserInfo.UserId
And DateValue(S.CheckTime) = DateValue(dbo_UserInfo.CheckTime))
And T.CheckTime <
(Select Max(S.CheckTime)
From dbo_UserInfo As S
Where S.UserId = dbo_UserInfo.UserId
And DateValue(S.CheckTime) = DateValue(dbo_UserInfo.CheckTime))
Having Count(*) > 1) As LBIn,
(Select Max(TimeValue(T.CheckTime))
From dbo_UserInfo As T
Where T.UserId = dbo_UserInfo.UserId
And DateValue(T.CheckTime) = DateValue(dbo_UserInfo.CheckTime)
And T.CheckTime >
(Select Min(S.CheckTime)
From dbo_UserInfo As S
Where S.UserId = dbo_UserInfo.UserId
And DateValue(S.CheckTime) = DateValue(dbo_UserInfo.CheckTime))
And T.CheckTime <
(Select Max(S.CheckTime)
From dbo_UserInfo As S
Where S.UserId = dbo_UserInfo.UserId
And DateValue(S.CheckTime) = DateValue(dbo_UserInfo.CheckTime))
Having Count(*) > 1) As LBOut
FROM
dbo_UserInfo
GROUP BY
dbo_UserInfo.UserId,
DateValue([CheckTime]);
From this you can easily calculate the work hours.由此您可以轻松计算工作时间。
Revised output:修改后的输出:
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