[英]All the possible combination and permutations with repetition on python
Essentially, I want to do基本上,我想做
def get_all_possible(N)
for i0 in range(N) :
for i1 in range(N) :
for i2 in range(N) :
... for iNm1 in range(N) : #Nm1 is N minus 1
yield [i0,i1,i2,i3,...,iNm1]
and make a list of all the possible combination of number 0-N
at each index and their permutations.并列出每个索引处数字
0-N
的所有可能组合及其排列。 So when N=4
then there should be 4^4
possible combinations to be output.因此,当
N=4
,应该输出4^4
可能的组合。 This nested for loop is not efficient, and the code is not easily expandable to general N
case.这种嵌套的 for 循环效率不高,代码也不容易扩展到一般的
N
情况。
A solution that helps readability is itertools.product
一个有助于提高可读性的解决方案是
itertools.product
import itertools
all_combs = list(itertools.product(range(4), repeat=4))
尝试itertools.permutations
或itertools.combinations
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