如果字符串包含特定字符串，则删除字符串和括号。 熊猫

Question

I'm trying to figure out how to remove string and brackets if a column have contains a certain string.

So in my column I can have two strings that contain brackets like this

col a
this is the text(text it is) and other information (COO: warning) some other information

What I can do is remove all text and brackets. But how do I just remove the string and brackets that contains COO: ??

cork_ing['DS VALUE Check'] = cork_ing['DS_VALUE'].str.replace(r"\(.*?\)","")

Can I modify the above code line just to remove and string with COO: ?

Answer 1

You could target terms in parentheses which only also contain the text COO , eg

cork_ing['DS VALUE Check'] = cork_ing['DS_VALUE'].str.replace(r'\([^)]*COO.*?\)', '')

Explanation of regex pattern:

\(     match literal (
[^)]*  then match zero or more non ) characters
COO    match 'COO'
.*?    match remaining content up until the first
\)     literal closing )

Answer 2

cork_ing['DS VALUE Check'] = cork_ing['DS_VALUE'].apply(lambda string: string.replace("(","").replace(")","") if "COO" in string else string)