正则表达式以两个字母字符开头，然后是任何数字

Question

I'm trying to create a very simple regex that accepts strings:

1. starts with two [A-Za-z] characters
2. ends with any number of digits

my code is:

Regex.IsMatch("AA00000000000", $"^[A-Za-z]{2}[0-9]*$")

but it returns False. Where am I wrong? I've already tested the same regex with the same input on regexstorm.net and it works.

Answer 1

Working for me with below code:

string pattern = @"^[A-Za-z]{2}[0-9]*$";
string str = "AA00000000000";
bool val = Regex.IsMatch(str, pattern);

Answer 2

你在正则表达式前面放了一个“$”，因为“{2}”部分将被解释为“2”，所以被评估的正则表达式看起来像这样：“^[A-Za-z ]2[0-9]*$”。

Answer 3

Regex.IsMatch method return boolean value. Please, try with this way. You can also try with using "$"