[英]How to map from JPA Object in spring boot
good day all: I have a little issue I want you help me to resolve.大家好:我有一个小问题希望你帮我解决。 My problem is the next, I have to find the shorter distance of the stores according to google maps and according the latitude and longitude, anyway, I have the query that do these, my problem is when I call to jparepository
it returns an array and I need to return me with a specific format.我的问题是下一个,我必须根据谷歌地图和经纬度找到更短的商店距离,无论如何,我有做这些的查询,我的问题是当我调用jparepository
它返回一个数组和我需要以特定格式返回给我。
This is my end-point I'm trying to get from jparepository
这是我试图从jparepository
获得的jparepository
@RequestMapping(value = "api/promos/distance/", method = RequestMethod.GET)
public ResponseEntity<?> distance(@RequestParam(required = false) Double latitude, Double longitude, Long radius) {
try {
return ResponseEntity.status(HttpStatus.OK)
.body(locationDAO.findDistance(latitude,longitude,radius));
} catch (Exception ex){
return ResponseEntity.status(HttpStatus.INTERNAL_SERVER_ERROR).body(ex.toString());
}
}
this is my repository with the params and return 2 values这是我的带有参数的存储库并返回 2 个值
@Query(value = "select sp.id as id, \n" +
" ( 6371 * acos( cos( radians(:latitude) ) \n" +
" * cos( radians( sp.latitude )) \n" +
" * cos( radians( sp.longitude ) - radians(:longitude)) \n" +
" + sin( radians(:latitude) ) \n" +
" * sin( radians( sp.latitude ) ) ) ) AS distance \n" +
" from promo_locations sp \n" +
"having distance < :radius ORDER BY distance ASC", nativeQuery = true)
List<Object> findDistance(
@Param("latitude") Double latitude,
@Param("longitude") Double longitude,
@Param("radius") Long radius);
and it show me this它向我展示了这个
[
[
1,
137.94383549078196
],
[
2,
137.94383549078196
]
]
but I need to show me in this format:但我需要以这种格式向我展示:
[
{
"id" : 1,
"distance" : 137.94383549078196
},
{
"id" : 2,
"distance" :137.94383549078196
}
]
If someone knows how to map or how to convert I will thank you so much如果有人知道如何映射或如何转换,我将非常感谢
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